Concept explainers
(a)
The light intensity at the surface of the light bulb.
(a)
Answer to Problem 36.83AP
The light intensity at the surface of the light bulb is
Explanation of Solution
Given info:
The diameter of the spherical light bulb is
Formula to calculate the intensity at the surface of the light bulb is,
Here,
Substitute
Conclusion:
Therefore, the light intensity at the surface of the light bulb is
(b)
The light intensity at a distance
(b)
Answer to Problem 36.83AP
The light intensity at a distance
Explanation of Solution
Given info: The diameter of the spherical light bulb is
Formula to calculate the intensity at a distance
,
Here,
Substitute
Conclusion:
Therefore, the light intensity at a distance
(c)
The diameter of the light bulb image.
(c)
Answer to Problem 36.83AP
The diameter of the light bulb image is
Explanation of Solution
Given info: The diameter of the spherical light bulb is
From the lens maker formula,
Here,
Substitute
Thus, the image distance is
Formula to calculate the magnification of the image,
Here,
Formula to calculate the magnification of the image in terms of image and object distance is,
Here,
Equate the equation (1) and (2) and then rearrange for
Substitute
Conclusion:
Therefore, the diameter of the light bulb image is
(d)
The light intensity of the image.
(d)
Answer to Problem 36.83AP
The light intensity of the image is
Explanation of Solution
Given info: The diameter of the spherical light bulb is
From part (b) the light intensity at a distance
From part (c) the diameter of the light bulb image is
Formula to calculate the power of lens is,
Here,
The area of the lens is,
Substitute
The area of the lens is
Substitute
Formula to calculate the required intensity of bulb light image,
The area of image is,
Substitute
Substitute
Conclusion:
Therefore, the light intensity of the image is
Want to see more full solutions like this?
Chapter 36 Solutions
Physics for Scientists and Engineers (AP Edition)
- No chatgpt pls will upvotearrow_forwardair is pushed steadily though a forced air pipe at a steady speed of 4.0 m/s. the pipe measures 56 cm by 22 cm. how fast will air move though a narrower portion of the pipe that is also rectangular and measures 32 cm by 22 cmarrow_forwardNo chatgpt pls will upvotearrow_forward
- 13.87 ... Interplanetary Navigation. The most efficient way to send a spacecraft from the earth to another planet is by using a Hohmann transfer orbit (Fig. P13.87). If the orbits of the departure and destination planets are circular, the Hohmann transfer orbit is an elliptical orbit whose perihelion and aphelion are tangent to the orbits of the two planets. The rockets are fired briefly at the depar- ture planet to put the spacecraft into the transfer orbit; the spacecraft then coasts until it reaches the destination planet. The rockets are then fired again to put the spacecraft into the same orbit about the sun as the destination planet. (a) For a flight from earth to Mars, in what direction must the rockets be fired at the earth and at Mars: in the direction of motion, or opposite the direction of motion? What about for a flight from Mars to the earth? (b) How long does a one- way trip from the the earth to Mars take, between the firings of the rockets? (c) To reach Mars from the…arrow_forwardNo chatgpt pls will upvotearrow_forwarda cubic foot of argon at 20 degrees celsius is isentropically compressed from 1 atm to 425 KPa. What is the new temperature and density?arrow_forward
- Calculate the variance of the calculated accelerations. The free fall height was 1753 mm. The measured release and catch times were: 222.22 800.00 61.11 641.67 0.00 588.89 11.11 588.89 8.33 588.89 11.11 588.89 5.56 586.11 2.78 583.33 Give in the answer window the calculated repeated experiment variance in m/s2.arrow_forwardNo chatgpt pls will upvotearrow_forwardCan you help me solve the questions pleasearrow_forward
- Can you help me solve these questions please so i can see how to do itarrow_forwardHow can i solve this if n1 (refractive index of gas) and n2 (refractive index of plastic) is not known. And the brewsters angle isn't knownarrow_forward2. Consider the situation described in problem 1 where light emerges horizontally from ground level. Take k = 0.0020 m' and no = 1.0001 and find at which horizontal distance, x, the ray reaches a height of y = 1.5 m.arrow_forward
- Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
- Glencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-Hill