Explanation Given info: The accommodation limits of eyes are 18 cm and 80 cm . Write the expression for the focal length of the eye glasses from the thin lens equation. 1 p + 1 q = 1 f (1) Here, p is the object distance. q is the image distance. f is the focal length. The image is on the same side as the object so the image distance is − 80 m and the object length for starlight going through a nearsighted person’s glasses is ∞ . Substitute − 80 cm for q and ∞ for p in the equation (1). 1 ∞ + 1 ( − 80 cm ) ( 10 − 2 m 1 cm ) = 1 f 1 f = 1 − 0.8 m = − 1.25 diopters Thus, the focal length is − 1.25 diopters . Write the expression for a nearby object which image is virtual. 1 p + 1 q = 1 f Substitute − 80 cm for q and − 1

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ISBN: 9781305804470

Author: Jewett

Publisher: CENGAGE LEARNING - CONSIGNMENT

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Chapter 36, Problem 36.61P

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The minimum distance from where the person can see object clearly.

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The minimum distance from where the person can see object clearly.

Solution Summary: The author explains that the minimum distance from where the person can see object clearly is 23.2cm.

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