(a) Explanation Given: The distance of patient from the mirror is 10.0 m and the radius of curvature is 0.550 m . Write the mirror equation. 1 p + 1 q = 1 f q = p f p − f (1) Here, p is the object distance. q is the image distance. f is the focal length of the mirror. Write the equation of focal length. f = − R 2 Here, R is the radius of curvature of the mirror. Substitute 0.550 m for R in above equation to find f . f = − ( 0.550 m ) 2 = − 0 (b) To determine Whether the image is upright or inverted. (c) To determine The magnification of the image.

9th Edition

ISBN: 8220100654428

Author: Jewett

Publisher: Cengage Learning US

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Chapter 36, Problem 36.12P

(a)

To determine

The location of image when the patient is 10.0 m distance away from the mirror.

(b)

To determine

Whether the image is upright or inverted.

(c)

To determine

The magnification of the image.

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Chapter 36, Problem 36.11P

Chapter 36, Problem 36.13P

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Chapter 36 Solutions

EBK PHYSICS FOR SCIENTISTS AND ENGINEER

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The location of image when the patient is 10.0 m distance away from the mirror.

Solution Summary: The author explains how to determine the location of image when the patient is 10.0m away from the mirror.

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The location of image when the patient is 10.0 m distance away from the mirror.

Whether the image is upright or inverted.

The magnification of the image.

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Chapter 36 Solutions