Algebra 2: New York Edition (holt Mcdougal Larson Algebra 2)
Algebra 2: New York Edition (holt Mcdougal Larson Algebra 2)
2nd Edition
ISBN: 9780618912407
Author: MCDOUGAL LITTEL
Publisher: Mcdougal Littel
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Equations and Inequations
Equations and inequalities describe the relationship between two mathematical expressions.
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A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.
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Chapter 3.6, Problem 31E
Solution

To calculate: The value of x for the equation 3x+432/3+22=38 and also check the solution.

The resultant answer is x=7 .

Given information:

The equation is 3x+432/3+22=38 .

Formula used:

Raise each side of the equation to the same power.

Calculation:

Write the original equation:

  3x+432/3+22=38

Subtract 22 from both sides of the equation,

  3x+432/3+22−22=38−223x+432/3=16

Raise each side to the power 32 and simplify,

  3x+432/332=16323x+43=1632

Rewrite using the property of exponent,

  3x+43=42323x+43=433x+43=64

Subtract 43 from both sides of the equation,

  3x+43−43=64−433x=21

Divide each side by 3,

  3x3=213x=7

Now check x=7 in the original equation.

  3x+432/3+22=38

Now substitute 7 for x and simplify,

  3⋅7+432/3+22=?3821+432/3+22=?38642/3+22=?384323+22=?3842+22=?3816+22=?3838=38

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Chapter 3.6, Problem 30E
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Chapter 3.6, Problem 32E

Chapter 3 Solutions

Algebra 2: New York Edition (holt Mcdougal Larson Algebra 2)

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