Explanation Given : The function is lim x → 0 + ( x − 1 − 1 2 x − 1 ) . Calculation: Apply the limit in the function as follows: lim x → 0 + ( x − 1 − 1 2 x − 1 ) = 0 0 Simplify and apply L’Hopital’s rule in the limit of the function as follows: lim x → 0 + ( x − 1 − 1 2 x − 1 ) = lim x → 0 + ( 1 x − 1 2 x − 1 ) = lim x → 0 + ( 2 x − 1 − x x ( 2 x − 1 ) ) = lim x → 0 + ( 2 x − 1 − x 2 x x − x

14th Edition

ISBN: 9781464140051

Author: TAALMAN, Laura, Kohn, Peter

Publisher: W. H. Freeman

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Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topic…

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Chapter 3.6, Problem 30S

To determine

To find: The limit of function limx→0+(x−1−12x−1) .

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Chapter 3.6, Problem 29S

Chapter 3.6, Problem 31S

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Chapter 3 Solutions

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The limit of function lim x → 0 + ( x − 1 − 1 2 x − 1 ) .

Solution Summary: The author explains the L'Hopital's rule in the limit of the function undersetxto infty .

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To find: The limit of function limx→0+(x−1−12x−1) .

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Chapter 3 Solutions