Explanation 1) Concept: We have the equation for Rayleigh’s criterion. We also have the relation between distance between two points, the length from which we are observing those points, and small angle. We rearrange the equation to find the required answer. 2) Formula: i) θ = D L ii) θ R = 1.22 λ d 3) Given: i) L = 400 k m = 400 × 10 3 m ii) d = 5 m m = 0.005 m iii) λ = 550 n m = 550 × 10 - 9 m 4) Calculation: a) We have θ = D L We can write this as D = θ L But according to Rayleigh’s criterion, θ R = 1.22 λ d D = 1

11th Edition

ISBN: 9781119459170

Author: Halliday

Publisher: WILEY

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Question

Chapter 36, Problem 22P

To determine

To find:

a) Smaller liner width on Earth’s surface that the astronaut can resolve

b) Can the astronaut resolve the Great Wall of China?

c) Would the astronaut be able to resolve any unmistakable sign of intelligent life on Earth’s surface?

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Chapter 36, Problem 21P

Chapter 36, Problem 23P

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Chapter 36 Solutions

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a) Smaller liner width on Earth’s surface that the astronaut can resolve b) Can the astronaut resolve the Great Wall of China? c) Would the astronaut be able to resolve any unmistakable sign of intelligent life on Earth’s surface?

Solution Summary: The author explains the equation for Rayleigh's criterion and the relation between distance between two points, length from which we are observing those points and small angle.

Concept explainers

To find: a) Smaller liner width on Earth’s surface that the astronaut can resolve b) Can the astronaut resolve the Great Wall of China? c) Would the astronaut be able to resolve any unmistakable sign of intelligent life on Earth’s surface?

Want to see the full answer?

Chapter 36 Solutions

To find:

a) Smaller liner width on Earth’s surface that the astronaut can resolve

b) Can the astronaut resolve the Great Wall of China?

c) Would the astronaut be able to resolve any unmistakable sign of intelligent life on Earth’s surface?