EBK 3N3-EBK: INDUSTRIAL MOTOR CONTROL
7th Edition
ISBN: 9780176919962
Author: Herman
Publisher: VST
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Textbook Question
Chapter 36, Problem 1RQ
List five common starting methods for three-phase squirrel-cage motors.
Expert Solution & Answer
To determine
The five common starting methods for three phase squirrel cage motors.
Explanation of Solution
Starters are used to limit the starting current for three phase squirrel cage induction motors. The most common starting methods for three phase squirrel cage motors are:
- 1. Across the line starting method
- 2. Resistor starting
- 3. Autotransformer starting
- 4. Y-delta starting
- 5. Part winding starting
Thus, the five common starting methods for three phase squirrel cage motors are listed.
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Students have asked these similar questions
Problem (17): water flowing in an open channel of a rectangular cross-section with width (b) transitions from a
mild slope to a steep slope (i.e., from subcritical to supercritical flow) with normal water depths of (y₁) and
(y2), respectively.
Given the values of y₁ [m], y₂ [m], and b [m], calculate the discharge in the channel (Q) in [Lit/s].
Givens:
y1 = 4.112 m
y2 =
0.387 m
b = 0.942 m
Answers:
( 1 ) 1880.186 lit/s
( 2 ) 4042.945 lit/s
( 3 ) 2553.11 lit/s
( 4 ) 3130.448 lit/s
Problem (14): A pump is being used to lift water from an underground
tank through a pipe of diameter (d) at discharge (Q). The total head
loss until the pump entrance can be calculated as (h₁ = K[V²/2g]), h
where (V) is the flow velocity in the pipe. The elevation difference
between the pump and tank surface is (h).
Given the values of h [cm], d [cm], and K [-], calculate the maximum
discharge Q [Lit/s] beyond which cavitation would take place at the
pump entrance. Assume Turbulent flow conditions.
Givens:
h = 120.31 cm
d = 14.455 cm
K = 8.976
Q
Answers:
(1) 94.917 lit/s
(2) 49.048 lit/s
( 3 ) 80.722 lit/s
68.588 lit/s
4
Problem (13): A pump is being used to lift water from the bottom
tank to the top tank in a galvanized iron pipe at a discharge (Q).
The length and diameter of the pipe section from the bottom tank
to the pump are (L₁) and (d₁), respectively. The length and
diameter of the pipe section from the pump to the top tank are
(L2) and (d2), respectively.
Given the values of Q [L/s], L₁ [m], d₁ [m], L₂ [m], d₂ [m],
calculate total head loss due to friction (i.e., major loss) in the
pipe (hmajor-loss) in [cm].
Givens:
L₁,d₁
Pump
L₂,d2
오
0.533 lit/s
L1 =
6920.729 m
d1 =
1.065 m
L2 =
70.946 m
d2
0.072 m
Answers:
(1)
3.069 cm
(2) 3.914 cm
( 3 ) 2.519 cm
( 4 ) 1.855 cm
TABLE 8.1
Equivalent Roughness for New Pipes
Pipe
Riveted steel
Concrete
Wood stave
Cast iron
Galvanized iron
Equivalent Roughness, &
Feet
Millimeters
0.003-0.03 0.9-9.0
0.001-0.01 0.3-3.0
0.0006-0.003 0.18-0.9
0.00085
0.26
0.0005
0.15
0.045
0.000005
0.0015
0.0 (smooth) 0.0 (smooth)
Commercial steel or wrought iron 0.00015
Drawn…
Chapter 36 Solutions
EBK 3N3-EBK: INDUSTRIAL MOTOR CONTROL
Ch. 36 - List five common starting methods for three-phase...Ch. 36 - Prob. 2RQCh. 36 - A squirrel-cage motor produces 1100 pound-feet of...Ch. 36 - What is the most common device used to disconnect...Ch. 36 - Prob. 5RQCh. 36 - Prob. 6RQCh. 36 - Prob. 7RQCh. 36 - Prob. 8RQCh. 36 - Prob. 9RQCh. 36 - Prob. 10RQ
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