You are conducting a single-slit diffraction experiment with light of wavelength λ . What appears, on a distant viewing screen, at a point at which the top and bottom rays through the slit have a path length difference equal to (a) 5 λ and (b) 4.5 λ ?

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Answer 1

Textbook Question

Chapter 36, Problem 1Q

You are conducting a single-slit diffraction experiment with light of wavelength λ. What appears, on a distant viewing screen, at a point at which the top and bottom rays through the slit have a path length difference equal to (a) 5λ and (b) 4.5λ?

Expert Solution & Answer

To determine

To find:

a) What appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 5λ.

b) What appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 4.5λ.

Answer to Problem 1Q

Solution:

a) m=5 minimum.

b) Maximum between the m=4 and m=5 (approximately).

Explanation of Solution

1) Concept:

Usingthe condition for occurrence of minimum in a single slit experiment, we can find what appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 5λ and 4.5λ.

2) Formula:

∆L=mλ

3) Given:

The single slit experiment is conducted with the light of wavelength λ.

4) Calculations:

a) In the single slit experiment, the condition for occurrence of minimum is

Path length difference=∆L=mλ For m=1,2,3

From this, we can interpret that at ∆L=5λ; m=5 minimum appears.

b) ∆L=4.5λ implies that it corresponds to approximately maximum between m=4 minimum and m=5 minimum.

Conclusion:

We can predict about what appears on screen in a single slit experiment from the condition for minimum.

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Answer 2

Textbook Question

Chapter 36, Problem 1Q

You are conducting a single-slit diffraction experiment with light of wavelength λ. What appears, on a distant viewing screen, at a point at which the top and bottom rays through the slit have a path length difference equal to (a) 5λ and (b) 4.5λ?

Expert Solution & Answer

To determine

To find:

a) What appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 5λ.

b) What appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 4.5λ.

Answer to Problem 1Q

Solution:

a) m=5 minimum.

b) Maximum between the m=4 and m=5 (approximately).

Explanation of Solution

1) Concept:

Usingthe condition for occurrence of minimum in a single slit experiment, we can find what appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 5λ and 4.5λ.

2) Formula:

∆L=mλ

3) Given:

The single slit experiment is conducted with the light of wavelength λ.

4) Calculations:

a) In the single slit experiment, the condition for occurrence of minimum is

Path length difference=∆L=mλ For m=1,2,3

From this, we can interpret that at ∆L=5λ; m=5 minimum appears.

b) ∆L=4.5λ implies that it corresponds to approximately maximum between m=4 minimum and m=5 minimum.

Conclusion:

We can predict about what appears on screen in a single slit experiment from the condition for minimum.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Textbook Question

Chapter 36, Problem 1Q

You are conducting a single-slit diffraction experiment with light of wavelength λ. What appears, on a distant viewing screen, at a point at which the top and bottom rays through the slit have a path length difference equal to (a) 5λ and (b) 4.5λ?

Expert Solution & Answer

To determine

To find:

a) What appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 5λ.

b) What appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 4.5λ.

Answer to Problem 1Q

Solution:

a) m=5 minimum.

b) Maximum between the m=4 and m=5 (approximately).

Explanation of Solution

1) Concept:

Usingthe condition for occurrence of minimum in a single slit experiment, we can find what appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 5λ and 4.5λ.

2) Formula:

∆L=mλ

3) Given:

The single slit experiment is conducted with the light of wavelength λ.

4) Calculations:

a) In the single slit experiment, the condition for occurrence of minimum is

Path length difference=∆L=mλ For m=1,2,3

From this, we can interpret that at ∆L=5λ; m=5 minimum appears.

b) ∆L=4.5λ implies that it corresponds to approximately maximum between m=4 minimum and m=5 minimum.

Conclusion:

We can predict about what appears on screen in a single slit experiment from the condition for minimum.

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Answer 4

Textbook Question

Chapter 36, Problem 1Q

You are conducting a single-slit diffraction experiment with light of wavelength λ. What appears, on a distant viewing screen, at a point at which the top and bottom rays through the slit have a path length difference equal to (a) 5λ and (b) 4.5λ?

Expert Solution & Answer

To determine

To find:

a) What appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 5λ.

b) What appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 4.5λ.

Answer to Problem 1Q

Solution:

a) m=5 minimum.

b) Maximum between the m=4 and m=5 (approximately).

Explanation of Solution

1) Concept:

Usingthe condition for occurrence of minimum in a single slit experiment, we can find what appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 5λ and 4.5λ.

2) Formula:

∆L=mλ

3) Given:

The single slit experiment is conducted with the light of wavelength λ.

4) Calculations:

a) In the single slit experiment, the condition for occurrence of minimum is

Path length difference=∆L=mλ For m=1,2,3

From this, we can interpret that at ∆L=5λ; m=5 minimum appears.

b) ∆L=4.5λ implies that it corresponds to approximately maximum between m=4 minimum and m=5 minimum.

Conclusion:

We can predict about what appears on screen in a single slit experiment from the condition for minimum.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution & Answer

To determine

To find:

a) What appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 5λ.

b) What appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 4.5λ.

Answer to Problem 1Q

Solution:

a) m=5 minimum.

b) Maximum between the m=4 and m=5 (approximately).

Explanation of Solution

1) Concept:

Usingthe condition for occurrence of minimum in a single slit experiment, we can find what appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 5λ and 4.5λ.

2) Formula:

∆L=mλ

3) Given:

The single slit experiment is conducted with the light of wavelength λ.

4) Calculations:

a) In the single slit experiment, the condition for occurrence of minimum is

Path length difference=∆L=mλ For m=1,2,3

From this, we can interpret that at ∆L=5λ; m=5 minimum appears.

b) ∆L=4.5λ implies that it corresponds to approximately maximum between m=4 minimum and m=5 minimum.

Conclusion:

We can predict about what appears on screen in a single slit experiment from the condition for minimum.

Answer 8

Expert Solution & Answer

To determine

To find:

a) What appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 5λ.

b) What appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 4.5λ.

Answer to Problem 1Q

Solution:

a) m=5 minimum.

b) Maximum between the m=4 and m=5 (approximately).

Explanation of Solution

1) Concept:

Usingthe condition for occurrence of minimum in a single slit experiment, we can find what appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 5λ and 4.5λ.

2) Formula:

∆L=mλ

3) Given:

The single slit experiment is conducted with the light of wavelength λ.

4) Calculations:

a) In the single slit experiment, the condition for occurrence of minimum is

Path length difference=∆L=mλ For m=1,2,3

From this, we can interpret that at ∆L=5λ; m=5 minimum appears.

b) ∆L=4.5λ implies that it corresponds to approximately maximum between m=4 minimum and m=5 minimum.

Conclusion:

We can predict about what appears on screen in a single slit experiment from the condition for minimum.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

To determine

To find:

a) What appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 5λ.

b) What appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 4.5λ.

Answer 12

Answer to Problem 1Q

Solution:

a) m=5 minimum.

b) Maximum between the m=4 and m=5 (approximately).

Answer 13

Explanation of Solution

1) Concept:

Usingthe condition for occurrence of minimum in a single slit experiment, we can find what appears on a distant viewing screen at a point at which the top and bottom rays through the slit have a path length difference equal to 5λ and 4.5λ.