Challenge Problem Removing a Discontinuity In Example 5 we graphed the rational function R ( x ) = 2 x 2 − 5 x + 2 x 2 − 4 and found that the graph has a hole at the point ( 2 , 3 4 ) . Therefore, the graph of R is discontinuous at ( 2 , 3 4 ) . We can remove this discontinuity by defining the rational function R using the following piecewise-defined function: R ( x ) = { 2 x 2 − 5 x + 2 x 2 − 4 if x ≠ 2 3 4 if x = 2 Redefine R from Problem 33 so that the discontinuity at x = 3 is removed. Redefine R from Problem 33 so that the discontinuity at x = 3 2 is removed. R ( x ) = x 2 + x − 12 x 2 − x − 6
Challenge Problem Removing a Discontinuity In Example 5 we graphed the rational function R ( x ) = 2 x 2 − 5 x + 2 x 2 − 4 and found that the graph has a hole at the point ( 2 , 3 4 ) . Therefore, the graph of R is discontinuous at ( 2 , 3 4 ) . We can remove this discontinuity by defining the rational function R using the following piecewise-defined function: R ( x ) = { 2 x 2 − 5 x + 2 x 2 − 4 if x ≠ 2 3 4 if x = 2 Redefine R from Problem 33 so that the discontinuity at x = 3 is removed. Redefine R from Problem 33 so that the discontinuity at x = 3 2 is removed. R ( x ) = x 2 + x − 12 x 2 − x − 6
Solution Summary: The author explains how to remove discontinuity at x=3 by redefining the function R(x).
Challenge Problem Removing a Discontinuity In Example
5
we graphed the rational function
R
(
x
)
=
2
x
2
−
5
x
+
2
x
2
−
4
and found that the graph has a hole at the point
(
2
,
3
4
)
. Therefore, the graph of
R
is discontinuous at
(
2
,
3
4
)
. We can remove this discontinuity by defining the rational function
R
using the following piecewise-defined function:
R
(
x
)
=
{
2
x
2
−
5
x
+
2
x
2
−
4
if
x
≠
2
3
4
if
x
=
2
Redefine
R
from Problem
33
so that the discontinuity at
x
=
3
is removed.
Redefine
R
from Problem
33
so that the discontinuity at
x
=
3
2
is removed.
Good Day,
Kindly assist me with the following query. Any assistance would be appreciated.
Can u give rough map of any room u can choose cm on top
3. We'd like to know the first time when the population reaches 7000 people. First, graph the
function from part (a) on your calculator or Desmos. In the same window, graph the line y =
7000. Notice that you will need to adjust your window so that you can see values as big as
7000! Investigate the intersection of the two graphs. (This video shows you how to find the
intersection on your calculator, or in Desmos just hover the cursor over the point.) At what
value t> 0 does the line intersect with your exponential function? Round your answer to two
decimal places. (You don't need to show work for this part.) (2 points)
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