EBK PHYSICS FOR SCIENTISTS AND ENGINEER
EBK PHYSICS FOR SCIENTISTS AND ENGINEER
1st Edition
ISBN: 9780100546714
Author: Katz
Publisher: YUZU
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 35, Problem 68PQ

(a)

To determine

The distance from the slit to the viewing screen.

(a)

Expert Solution
Check Mark

Answer to Problem 68PQ

The distance from the slit to the viewing screen is 2.1m.

Explanation of Solution

Write the expression for the minima of single slit diffraction pattern to find sinθm.

  wsinθm=mλsinθm=mλw                          (I)

Here, w is width of the slit and m is an integer (m=±1,±2,±3,.........), θ is the angular position and λ is the wavelength of light.

Substitute m=1 for the first minima in above equation to find sinθ1.

  sinθ1=λw                                (II)

Write the equation for the width of the central maximum which is surrounded by the first minima.

  B=2y1=2xtanθ1                            (III)

Here, B is the width of central maximum and x is the distance from the slit to the screen.

For small angle of θ1, tanθ1sinθ1.

Substitute λw for tanθ1 in above equation to find x.

  B=2x(λw)x=Bw2λ                            (IV)

Conclusion:

Substitute 6.60mm for B, 0.314mm for w and 490.0nm for λ in equation (IV) to find x.

  x=(6.60mm×10-3m1mm)(0.314mm×10-3m1mm)2(490.0nm×10-9m1nm)=2.1m

Therefore, the distance from the slit to the viewing screen is 2.1m.

(b)

To determine

The width of the first side maximum on the viewing screen.

(b)

Expert Solution
Check Mark

Answer to Problem 68PQ

The width of the first side maximum on the viewing screen is 3.32mm.

Explanation of Solution

Substitute m=2 for the second minima in equation (I) to find sinθ2.

  sinθ2=2λw                                (V)

Write the equation for the distance from the center of the central maximum to the second minima.

  y2=xtanθ2                                  (VI)

For small angle of θ2, tanθ2sinθ2.

Substitute 2λw for tanθ2 in above equation to find y2.

  y2=2λxw                                     (VII)

Substitute m=1 for the second minima in equation (I) to find sinθ2.

  y1=λxw                                     (VIII)

Write Δy from Equations (VII) and (VIII).

Δy=y2y1=λxw

Conclusion:

Substitute 490.0nm for λ, 2.1m for x and 0.314mm for w in equation (VII) to find y2.

  Δy=(490.0nm×10-9m1nm)×2.1m(0.314mm×10-3m1mm)=3.32×103m×1mm10-3m=3.32mm

Therefore, the width of the first side maximum on the viewing screen is 3.32mm.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
A golf club hits a golf ball and the golf ball’s flight reaches a maximum height of 5.48 m. Calculate the momentum of the golf ball at the maximum height if the mass of the golf ball is 0.459 kg.
• Superposition Theorem • Thevenin's and Norton's Theorem 1. Find the unknown voltage V₁, unknown resistances R1 and R2, and currents flowing through R1 and R2 for the circuit shown below using Superposition Theorem. 40 V + R₁₂ w B C ♥16A 10A www 4A F ww 2 E Ꭰ 2. Use Thevenin's Theorem to find the current flowing in 3-ohm resistor and its power dissipation from the circuit shown in the right. + 3. Use Norton's Theorem for the same instruction as for No. 2. 8 V A www 202 B wwww 20 Ω 10 V + 302 202 www C - 12 V 502 www.
Fill in blanks

Chapter 35 Solutions

EBK PHYSICS FOR SCIENTISTS AND ENGINEER

Ch. 35 - Prob. 5PQCh. 35 - Prob. 6PQCh. 35 - A student shines a red laser pointer with a...Ch. 35 - Monochromatic light is incident on a pair of slits...Ch. 35 - Prob. 9PQCh. 35 - In a Youngs double-slit experiment with microwaves...Ch. 35 - A beam from a helium-neon laser with wavelength...Ch. 35 - Prob. 12PQCh. 35 - Prob. 13PQCh. 35 - Prob. 14PQCh. 35 - Light from a sodium vapor lamp ( = 589 nm) forms...Ch. 35 - Prob. 16PQCh. 35 - Prob. 17PQCh. 35 - Prob. 18PQCh. 35 - Prob. 19PQCh. 35 - Prob. 20PQCh. 35 - Prob. 21PQCh. 35 - Prob. 22PQCh. 35 - Prob. 23PQCh. 35 - Figure P35.24 shows the diffraction patterns...Ch. 35 - Prob. 25PQCh. 35 - Prob. 26PQCh. 35 - A thread must have a uniform thickness of 0.525...Ch. 35 - Prob. 28PQCh. 35 - Prob. 29PQCh. 35 - A radio wave of wavelength 21.5 cm passes through...Ch. 35 - Prob. 31PQCh. 35 - Prob. 32PQCh. 35 - A single slit is illuminated by light consisting...Ch. 35 - Prob. 34PQCh. 35 - Prob. 35PQCh. 35 - Prob. 36PQCh. 35 - Prob. 37PQCh. 35 - Prob. 38PQCh. 35 - Prob. 39PQCh. 35 - Prob. 40PQCh. 35 - Prob. 41PQCh. 35 - Prob. 42PQCh. 35 - Prob. 43PQCh. 35 - Prob. 44PQCh. 35 - Prob. 45PQCh. 35 - Prob. 46PQCh. 35 - Prob. 47PQCh. 35 - Prob. 48PQCh. 35 - Figure P35.49 shows the intensity of the...Ch. 35 - Prob. 50PQCh. 35 - Prob. 51PQCh. 35 - Prob. 52PQCh. 35 - Light of wavelength 750.0 nm passes through a...Ch. 35 - Prob. 54PQCh. 35 - Prob. 55PQCh. 35 - Prob. 56PQCh. 35 - Light of wavelength 515 nm is incident on two...Ch. 35 - Light of wavelength 515 nm is incident on two...Ch. 35 - A Two slits are separated by distance d and each...Ch. 35 - Prob. 60PQCh. 35 - Prob. 61PQCh. 35 - If you spray paint through two slits, what pattern...Ch. 35 - Prob. 63PQCh. 35 - Prob. 64PQCh. 35 - Prob. 65PQCh. 35 - Prob. 66PQCh. 35 - Prob. 67PQCh. 35 - Prob. 68PQCh. 35 - Prob. 69PQCh. 35 - Prob. 70PQCh. 35 - Prob. 71PQCh. 35 - Prob. 72PQCh. 35 - Prob. 73PQCh. 35 - Prob. 74PQCh. 35 - Prob. 75PQCh. 35 - Prob. 76PQCh. 35 - Prob. 77PQCh. 35 - Another way to construct a double-slit experiment...Ch. 35 - Prob. 79PQCh. 35 - Prob. 80PQCh. 35 - Table P35.80 presents data gathered by students...Ch. 35 - Prob. 82PQCh. 35 - Prob. 83PQCh. 35 - Prob. 84PQCh. 35 - Prob. 85PQCh. 35 - Prob. 86PQCh. 35 - Prob. 87PQCh. 35 - Prob. 88PQCh. 35 - A One of the slits in a Youngs double-slit...Ch. 35 - Prob. 90PQ
Knowledge Booster
Background pattern image
Physics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
University Physics Volume 3
Physics
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:OpenStax
Text book image
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Text book image
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
Diffraction of light animation best to understand class 12 physics; Author: PTAS: Physics Tomorrow Ambition School;https://www.youtube.com/watch?v=aYkd_xSvaxE;License: Standard YouTube License, CC-BY