EBK PHYSICS FOR SCIENTISTS AND ENGINEER
16th Edition
ISBN: 8220100546716
Author: Katz
Publisher: CENGAGE L
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Chapter 35, Problem 42PQ
To determine
The expression for angular width
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10. Imagine you have a system in which you have 54 grams of ice. You can melt this
ice and then vaporize it all at 0 C. The melting and vaporization are done reversibly
into a balloon held at a pressure of 0.250 bar. Here are some facts about water you
may wish to know. The density of liquid water at 0 C is 1 g/cm³. The density of ice at 0
C is 0.917 g/cm³. The enthalpy of vaporization of liquid water is 2.496 kJ/gram and the
enthalpy of fusion of solid water is 333.55 J/gram.
Consider 1 mole of supercooled water at -10°C. Calculate the entropy change of the water when the
supercooled water freezes at -10°C and 1 atm.
Useful data:
Cp (ice) = 38 J mol-1 K-1
Cp (water) 75J mol −1
K
-1
Afus H (0°C) 6026 J mol −1
Assume Cp (ice) and Cp (water) to be independent of temperature.
The molar enthalpy of vaporization of benzene at its normal boiling point (80.09°C) is 30.72 kJ/mol.
Assuming that AvapH and AvapS stay constant at their values at 80.09°C, calculate the value of
AvapG at 75.0°C, 80.09°C, and 85.0°C.
Hint: Remember that the liquid and vapor phases will be in equilibrium at the normal boiling point.
Chapter 35 Solutions
EBK PHYSICS FOR SCIENTISTS AND ENGINEER
Ch. 35.1 - Perhaps Newton never observed a diffraction...Ch. 35.1 - Prob. 35.2CECh. 35.2 - Prob. 35.3CECh. 35.3 - Prob. 35.4CECh. 35.4 - When we studied Youngs double-slit experiment, we...Ch. 35.6 - Prob. 35.6CECh. 35 - Light Is a Wave C As shown in Figure P35.1, spray...Ch. 35 - Sound Wave Interference Revisited Draw two...Ch. 35 - Prob. 3PQCh. 35 - You are seated on a couch equidistant between two...
Ch. 35 - Prob. 5PQCh. 35 - Prob. 6PQCh. 35 - A student shines a red laser pointer with a...Ch. 35 - Monochromatic light is incident on a pair of slits...Ch. 35 - Prob. 9PQCh. 35 - In a Youngs double-slit experiment with microwaves...Ch. 35 - A beam from a helium-neon laser with wavelength...Ch. 35 - Prob. 12PQCh. 35 - Prob. 13PQCh. 35 - Prob. 14PQCh. 35 - Light from a sodium vapor lamp ( = 589 nm) forms...Ch. 35 - Prob. 16PQCh. 35 - Prob. 17PQCh. 35 - Prob. 18PQCh. 35 - Prob. 19PQCh. 35 - Prob. 20PQCh. 35 - Prob. 21PQCh. 35 - Prob. 22PQCh. 35 - Prob. 23PQCh. 35 - Figure P35.24 shows the diffraction patterns...Ch. 35 - Prob. 25PQCh. 35 - Prob. 26PQCh. 35 - A thread must have a uniform thickness of 0.525...Ch. 35 - Prob. 28PQCh. 35 - Prob. 29PQCh. 35 - A radio wave of wavelength 21.5 cm passes through...Ch. 35 - Prob. 31PQCh. 35 - Prob. 32PQCh. 35 - A single slit is illuminated by light consisting...Ch. 35 - Prob. 34PQCh. 35 - Prob. 35PQCh. 35 - Prob. 36PQCh. 35 - Prob. 37PQCh. 35 - Prob. 38PQCh. 35 - Prob. 39PQCh. 35 - Prob. 40PQCh. 35 - Prob. 41PQCh. 35 - Prob. 42PQCh. 35 - Prob. 43PQCh. 35 - Prob. 44PQCh. 35 - Prob. 45PQCh. 35 - Prob. 46PQCh. 35 - Prob. 47PQCh. 35 - Prob. 48PQCh. 35 - Figure P35.49 shows the intensity of the...Ch. 35 - Prob. 50PQCh. 35 - Prob. 51PQCh. 35 - Prob. 52PQCh. 35 - Light of wavelength 750.0 nm passes through a...Ch. 35 - Prob. 54PQCh. 35 - Prob. 55PQCh. 35 - Prob. 56PQCh. 35 - Light of wavelength 515 nm is incident on two...Ch. 35 - Light of wavelength 515 nm is incident on two...Ch. 35 - A Two slits are separated by distance d and each...Ch. 35 - Prob. 60PQCh. 35 - Prob. 61PQCh. 35 - If you spray paint through two slits, what pattern...Ch. 35 - Prob. 63PQCh. 35 - Prob. 64PQCh. 35 - Prob. 65PQCh. 35 - Prob. 66PQCh. 35 - Prob. 67PQCh. 35 - Prob. 68PQCh. 35 - Prob. 69PQCh. 35 - Prob. 70PQCh. 35 - Prob. 71PQCh. 35 - Prob. 72PQCh. 35 - Prob. 73PQCh. 35 - Prob. 74PQCh. 35 - Prob. 75PQCh. 35 - Prob. 76PQCh. 35 - Prob. 77PQCh. 35 - Another way to construct a double-slit experiment...Ch. 35 - Prob. 79PQCh. 35 - Prob. 80PQCh. 35 - Table P35.80 presents data gathered by students...Ch. 35 - Prob. 82PQCh. 35 - Prob. 83PQCh. 35 - Prob. 84PQCh. 35 - Prob. 85PQCh. 35 - Prob. 86PQCh. 35 - Prob. 87PQCh. 35 - Prob. 88PQCh. 35 - A One of the slits in a Youngs double-slit...Ch. 35 - Prob. 90PQ
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- 3. The entropy of an ideal gas is S = Nkg In V. Entropy is a state function rather than a path function, and in this problem, you will show an example of the entropy change for an ideal gas being the same when you go between the same two states by two different pathways. A. Express ASV = S2 (V2) - S₁(V1), the change in entropy upon changing the volume from V₁to V2, at fixed particle number N and energy, U. B. Express ASN = S₂(N₂) - S₁ (N₁), the change in entropy upon changing the particle number from N₁ to N2, at fixed volume V and energy U. C. Write an expression for the entropy change, AS, for a two-step process (V₁, N₁) → (V2, N₁) → (V2, N₂) in which the volume changes first at fixed particle number, then the particle number changes at fixed volume. Again, assume energy is constant.arrow_forwardPlease don't use Chatgpt will upvote and give handwritten solutionarrow_forward6. We used the constant volume heat capacity, Cv, when we talked about thermodynamic cycles. It acts as a proportionality constant between energy and temperature: dU = C₁dT. You can also define a heat capacity for constant pressure processes, Cp. You can think of enthalpy playing a similar role to energy, but for constant pressure processes δαρ C = (37) - Sup Ср ат P = ат Starting from the definition of enthalpy, H = U + PV, find the relationship between Cy and Cp for an ideal gas.arrow_forward
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