Finding Derivatives Implicitly andExplicitly In Exercises 27–30, (a) find twoexplicit functions by solving the equation for y interms of x, (b) sketch the graph of the equation andlabel the parts given by the corresponding explicitfunctions, (c) differentiate the explicit functions,and (d) find dy dx implicitly and show that theresult is equivalent to that of part (c). 27. x2 + y2 = 64
Finding Derivatives Implicitly andExplicitly In Exercises 27–30, (a) find twoexplicit functions by solving the equation for y interms of x, (b) sketch the graph of the equation andlabel the parts given by the corresponding explicitfunctions, (c) differentiate the explicit functions,and (d) find dy dx implicitly and show that theresult is equivalent to that of part (c). 27. x2 + y2 = 64
Finding Derivatives Implicitly andExplicitly In Exercises 27–30, (a) find twoexplicit functions by solving the equation for y interms of x, (b) sketch the graph of the equation andlabel the parts given by the corresponding explicitfunctions, (c) differentiate the explicit functions,and (d) find dy dx implicitly and show that theresult is equivalent to that of part (c). 27. x2 + y2 = 64
Finding Derivatives Implicitly and Explicitly In Exercises 27–30, (a) find two explicit functions by solving the equation for y in terms of x, (b) sketch the graph of the equation and label the parts given by the corresponding explicit functions, (c) differentiate the explicit functions, and (d) find dy dx implicitly and show that the result is equivalent to that of part (c).
27. x2 + y2 = 64
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
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