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Chapter 35, Problem 20P

Figure P35.20 (page 958) shows a curved surface separating a material with index of refraction n1 from a material with index n2. The surface forms an image I of object O. The ray shown in red passes through the surface along a radial line. Its angles of incidence and refraction are both zero, so its direction does not change at the surface. For the ray shown in blue, the direction changes according to Snell’s law, n1 sin θ1 = n2 sin θ2. For paraxial rays, we assume θ1, and θ2 are small, so we may write n1 tan θ1 = n2 tan θ2. The magnification is defined as M = h′/h. Prove that the magnification is given by M = −n1q/n2p.

Figure P35.20

Chapter 35, Problem 20P, Figure P35.20 (page 958) shows a curved surface separating a material with index of refraction n1

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The force of the quadriceps (Fq) and force of the patellar tendon (Fp) is identical (i.e., 1000 N each). In the figure below angle in blue is Θ and the in green is half Θ (i.e., Θ/2). A) Calculate the patellar reaction force (i.e., R resultant vector is the sum of the horizontal component of the quadriceps and patellar tendon force) at the following joint angles: you need to provide a diagram showing the vector and its components for each part. a1) Θ = 160 degrees, a2) Θ = 90 degrees. NOTE: USE ONLY TRIGNOMETRIC FUNCTIONS (SIN/TAN/COS, NO LAW OF COSINES, NO COMPLICATED ALGEBRAIC EQUATIONS OR ANYTHING ELSE, ETC. Question A has 2 parts!
The force of the quadriceps (Fq) and force of the patellar tendon (Fp) is identical (i.e., 1000 N each). In the figure below angle in blue is Θ and the in green is half Θ (i.e., Θ/2). A) Calculate the patellar reaction force (i.e., R resultant vector is the sum of the horizontal component of the quadriceps and patellar tendon force) at the following joint angles: you need to provide a diagram showing the vector and its components for each part. a1) Θ = 160 degrees, a2) Θ = 90 degrees. NOTE: USE DO NOT USE LAW OF COSINES, NO COMPLICATED ALGEBRAIC EQUATIONS OR ANYTHING ELSE, ETC. Question A has 2 parts!
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Chapter 35 Solutions

Bundle: Physics For Scientists And Engineers With Modern Physics, 10th + Webassign Printed Access Card For Serway/jewett's Physics For Scientists And Engineers, 10th, Multi-term

Ch. 35 - Prob. 4PCh. 35 - Prob. 5PCh. 35 - Prob. 6PCh. 35 - An object of height 2.00 cm is placed 30.0 cm from...Ch. 35 - Prob. 8PCh. 35 - Prob. 9PCh. 35 - A concave spherical mirror has a radius of...Ch. 35 - Prob. 11PCh. 35 - Prob. 12PCh. 35 - Prob. 13PCh. 35 - Prob. 14PCh. 35 - Prob. 15PCh. 35 - Prob. 16PCh. 35 - One end of a long glass rod (n = 1.50) is formed...Ch. 35 - Prob. 18PCh. 35 - Prob. 19PCh. 35 - Figure P35.20 (page 958) shows a curved surface...Ch. 35 - To dress up your dorm room, you have purchased a...Ch. 35 - You are working for a solar energy company. Your...Ch. 35 - Prob. 23PCh. 35 - An objects distance from a converging lens is 5.00...Ch. 35 - Prob. 25PCh. 35 - Prob. 26PCh. 35 - A converging lens has a focal length of 10.0 cm....Ch. 35 - Prob. 28PCh. 35 - Prob. 29PCh. 35 - In Figure P35.30, a thin converging lens of focal...Ch. 35 - Prob. 31PCh. 35 - Prob. 32PCh. 35 - Two rays traveling parallel to the principal axis...Ch. 35 - Prob. 34PCh. 35 - Prob. 35PCh. 35 - Prob. 36PCh. 35 - Prob. 37PCh. 35 - Prob. 38PCh. 35 - Prob. 39PCh. 35 - The intensity I of the light reaching the CCD in a...Ch. 35 - Prob. 41PCh. 35 - Prob. 42PCh. 35 - A simple model of the human eye ignores its lens...Ch. 35 - Prob. 44APCh. 35 - Prob. 45APCh. 35 - The distance between an object and its upright...Ch. 35 - Prob. 47APCh. 35 - Two converging lenses having focal lengths of f1 =...Ch. 35 - Two lenses made of kinds of glass having different...Ch. 35 - Prob. 50APCh. 35 - Prob. 51APCh. 35 - Prob. 52APCh. 35 - Prob. 53APCh. 35 - In many applications, it is necessary to expand or...Ch. 35 - Prob. 55APCh. 35 - A zoom lens system is a combination of lenses that...Ch. 35 - Prob. 57CPCh. 35 - Prob. 58CP
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