EBK PHYSICS FOR SCIENTISTS AND ENGINEER
6th Edition
ISBN: 9781319321710
Author: Mosca
Publisher: VST
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Chapter 35, Problem 15P
(a)
To determine
The order of magnitude of the probability that the electron will tunnel through the barrier.
(b)
To determine
The order of magnitude of the probability that the electron will tunnel through a width of
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A 3.0 MeV proton is incident on a potential energy barrier of thickness 10 fm and height 10 MeV.What are (a) the transmission coefficient T, (b) the kinetic energy Kt the proton will have on the other side of the barrier if it tunnels through the barrier, and (c) the kinetic energy Kr it will have if it reflects from the barrier? A 3.0 MeV deuteron (the same charge but twice the mass as a proton) is incident on the same barrier.What are (d) T, (e) Kt, and (f) Kr?
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Chapter 35 Solutions
EBK PHYSICS FOR SCIENTISTS AND ENGINEER
Ch. 35 - Prob. 1PCh. 35 - Prob. 2PCh. 35 - Prob. 3PCh. 35 - Prob. 4PCh. 35 - Prob. 5PCh. 35 - Prob. 6PCh. 35 - Prob. 7PCh. 35 - Prob. 8PCh. 35 - Prob. 9PCh. 35 - Prob. 10P
Ch. 35 - Prob. 11PCh. 35 - Prob. 12PCh. 35 - Prob. 13PCh. 35 - Prob. 14PCh. 35 - Prob. 15PCh. 35 - Prob. 16PCh. 35 - Prob. 17PCh. 35 - Prob. 18PCh. 35 - Prob. 19PCh. 35 - Prob. 20PCh. 35 - Prob. 21PCh. 35 - Prob. 22PCh. 35 - Prob. 23PCh. 35 - Prob. 24PCh. 35 - Prob. 25PCh. 35 - Prob. 26PCh. 35 - Prob. 27PCh. 35 - Prob. 28PCh. 35 - Prob. 29PCh. 35 - Prob. 30PCh. 35 - Prob. 31PCh. 35 - Prob. 32PCh. 35 - Prob. 33PCh. 35 - Prob. 34PCh. 35 - Prob. 35PCh. 35 - Prob. 36PCh. 35 - Prob. 37PCh. 35 - Prob. 38P
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- A beam of electrons is incident on a barrier that is 0.60 nm wide and 6.40 eV high. If the number of electrons striking the barrier each second is 6.50 ✕ 1021 /s with an energy of 5.35 eV, then how long would it take for a single electron to be transmitted through the barrier?arrow_forwardThe energy of a proton is 1.0 MeV below the top of a 6.8-fm-wide energy barrier. What is the probability that the proton will tunnel through the barrier? (1 eV = 1.60 × 10-19 J, mproton = 1.67 × 10-27 kg, ħ = 1.055 × 10-34 J ∙ s, h = 6.626 × 10-34 J ∙ s)arrow_forwardAn electron is confined between two perfectly reflecting walls separated by the distance 12 x 10-11m. Use the Heisenberg uncertainty relation to estimate the lowest energy that the particle can have (in eV).arrow_forward
- An electron is bound in a square well of width 1.50 nm and depth U0 = 6E1-IDW. If the electron is initially in the ground level and absorbs a photon, what maximum wavelength can the photon have and still liberate the electron from the well?arrow_forwardA stream of electrons is of energy E is incident on a potential barrier of height U and thickness d. Even though U >> E, 5% of the electrons tunnel through the barrier. If the thickness of the barrier decrease to 0.12 d, what percentage of the electrons will tunnel through?arrow_forwardPlease type instead of hand writtingarrow_forward
- If the position of an electron in a membrane is measured to an accuracy of 3.58 µm, what is the electron's minimum uncertainty in velocity (in m/s)? a) If the electron has this velocity, what is its kinetic energy in eV? b) What are the implications of this energy, comparing it to typical molecular binding energies?arrow_forwardAn electron of energy 1 eV got trapped inside the surface of a metal. If the potential barrier is 4.0 eV and width of the barrier is 2 Angstrom, the probability of its transmission is, * O 0.01 0.09 0.5 0.085arrow_forwardWe can approximate an electron moving in a nanowire (a small, thin wire) as a one-dimensional infi nite square-well potential. Let the wire be 2.0 μm long. The nanowire is cooled to a temperature of 13 K, and we assume the electron’s average kinetic energy is that of gas molecules at this temperature ( 3kT/2). (a) What are the three lowest possible energy levels of the electrons? (b) What is the approximate quantum number of electrons moving in the wire?arrow_forward
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