Explanation Graphical method can be used to determine the position and size of an image formed by a thin lens. This can also be used to find the position from which a particular ray has been emanated. The lens in the figure is of diverging type. The rules for the diverging lens are that the parallel incident ray appears after refraction to have come from the second focal point, the ray through center of lens does not deviate appreciably and ray aimed at first focal point emerges parallel to the axis. The diagram showing the origin of the four rays are drawn in figure 1.

University Physics with Modern Physics (14th Edition)

14th Edition

ISBN: 9780321973610

Author: Hugh D. Young, Roger A. Freedman

Publisher: PEARSON

See similar textbooks

Concept explainers

Refraction of Light

Refraction is a change in the direction of light rays when they travel from one medium to another. It is the bending of light when it goes through different media.

Angle of Refraction

Light is considered by many scientists to have dual nature, both particle nature and wave nature. First, Particle nature is one in which we consider a stream of packets of energy called photons. Second, Wave nature is considering light as electromagnetic…

Index of Refraction of Diamond

Diamond, the world’s hardest naturally occurring material and mineral known, is a solid form of the element carbon. The atoms are arranged in a crystal structure called diamond cubic. They exist in a huge variety of colours. Also, they are one of the bes…

Videos

Question

Chapter 34.4, Problem 34.4TYU

To determine

The rays among A, B, C and D which will emanate from point Q at the top of the object

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 34.3, Problem 34.3TYU

Chapter 34.5, Problem 34.5TYU

Students have asked these similar questions

1) Consider two positively charged particles, one of charge q0 (particle 0) fixed at the origin, and another of charge q1 (particle 1) fixed on the y-axis at (0,d1,0). What is the net force F→ on particle 0 due to particle 1? Express your answer (a vector) using any or all of k, q0, q1, d1, i^, j^, and k^. 2) Now add a third, negatively charged, particle, whose charge is −q2− (particle 2). Particle 2 fixed on the y-axis at position (0,d2,0). What is the new net force on particle 0, from particle 1 and particle 2? Express your answer (a vector) using any or all of k, q0, q1, q2, d1, d2, i^, j^, and k^. 3) Particle 0 experiences a repulsion from particle 1 and an attraction toward particle 2. For certain values of d1 and d2, the repulsion and attraction should balance each other, resulting in no net force. For what ratio d1/d2 is there no net force on particle 0? Express your answer in terms of any or all of the following variables: k, q0, q1, q2.

A 85 turn, 10.0 cm diameter coil rotates at an angular velocity of 8.00 rad/s in a 1.35 T field, starting with the normal of the plane of the coil perpendicular to the field. Assume that the positive max emf is reached first. (a) What (in V) is the peak emf? 7.17 V (b) At what time (in s) is the peak emf first reached? 0.196 S (c) At what time (in s) is the emf first at its most negative? 0.589 x s (d) What is the period (in s) of the AC voltage output? 0.785 S

A bobsled starts at the top of a track as human runners sprint from rest and then jump into the sled. Assume they reach 40 km/h from rest after covering a distance of 50 m over flat ice. a. How much work do they do on themselves and the sled which they are pushing given the fact that there are two men of combined mass 185 kg and the sled with a mass of 200 kg? (If you haven't seen bobsledding, watch youtube to understand better what's going on.) b. After this start, the team races down the track and descends vertically by 200 m. At the finish line the sled crosses with a speed of 55 m/s. How much energy was lost to drag and friction along the way down after the men were in the sled?

Chapter 34 Solutions

University Physics with Modern Physics (14th Edition)

Ch. 34.1 - If you walk directly toward a plane mirror at a...Ch. 34.2 - A cosmetics mirror is designed so that your...Ch. 34.3 - The water droplets in Fig. 34.23 have radius of...Ch. 34.4 - Prob. 34.4TYU Ch. 34.5 - When used with 35-mm film (image area 24 mm 36...Ch. 34.6 - A certain eyeglass lens is thin at its center,...Ch. 34.7 - You are using a magnifier to examine a gem. If you...Ch. 34.8 - Which gives a lateral magnification of greater...Ch. 34 - A spherical mirror is cut in half horizontally....Ch. 34 - For the situation shown in Fig. 34.3, is the image...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

The rays among A, B, C and D which will emanate from point Q at the top of the object

Solution Summary: The author explains that graphical method can be used to determine the position and size of an image formed by a thin lens.

Concept explainers

Videos

The rays among A, B, C and D which will emanate from point Q at the top of the object

Want to see the full answer?

Chapter 34 Solutions