AUTOMOTIVE TECHNOLOGY -W/MINDTAP ACCESS
7th Edition
ISBN: 9780357096789
Author: ERJAVEC
Publisher: CENGAGE L
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Chapter 34, Problem 6SA
How do you test the efficiency of a secondary AIR system?
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Chapter 34 Solutions
AUTOMOTIVE TECHNOLOGY -W/MINDTAP ACCESS
Ch. 34 - A rich air-fuel ratio causes HC emissions to...Ch. 34 - What will result from too little EGR flow? And...Ch. 34 - What can result from a charcoal canister that is...Ch. 34 - What happens if a PCV valve is stuck in the open...Ch. 34 - Explain why the I/M 240 and similar tests are...Ch. 34 - How do you test the efficiency of a secondary AIR...Ch. 34 - List five common causes for high HC emissions.Ch. 34 - Describe carbon monoxide (CO) emissions in...Ch. 34 - An EGR valve that does not fully close can cause...Ch. 34 - A restricted catalytic converter can cause all of...
Ch. 34 - Which of the following statements about EVAP...Ch. 34 - As a catalytic converter begins to deteriorate,...Ch. 34 - How much pressure does a typical EVAP pressure...Ch. 34 - Which of the following exhaust gases is typically...Ch. 34 - Prob. 7MCCh. 34 - While discussing the proper way to test a...Ch. 34 - Prob. 2ASRQCh. 34 - While discussing catalytic converter diagnosis:...Ch. 34 - While discussing EGR valve diagnosis: Technician A...Ch. 34 - While discussing EGR valve diagnosis: Technician A...Ch. 34 - When discussing the diagnosis of a positive back...Ch. 34 - While diagnosing a PCV problem: Technician A says...Ch. 34 - Technician A says that the AIR system should pump...Ch. 34 - While discussing PCV system diagnosis: Technician...Ch. 34 - While discussing EVAP testing: Technician A says...
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- 3. Find a basis of eigenvectors and diagonalize. 4 0 -19 7 a. b. 1-42 16 12-20 [21-61arrow_forward2. Find the eigenvalues. Find the corresponding eigenvectors. 6 2 -21 [0 -3 1 3 31 a. 2 5 0 b. 3 0 -6 C. 1 1 0 -2 0 7 L6 6 0 1 1 2. (Hint: λ = = 3)arrow_forwardUSE MATLAB ONLY provide typed code solve for velocity triangle and dont provide copied answer Turbomachienery . GIven: vx = 185 m/s, flow angle = 60 degrees, (leaving a stator in axial flow) R = 0.5, U = 150 m/s, b2 = -a3, a2 = -b3 Find: velocity triangle , a. magnitude of abs vel leaving rotor (m/s) b. flow absolute angles (a1, a2, a3) 3. flow rel angles (b2, b3) d. specific work done e. use code to draw vel. diagram Use this code for plot % plots Velocity Tri. in Ch4 function plotveltri(al1,al2,al3,b2,b3) S1L = [0 1]; V1x = [0 0]; V1s = [0 1*tand(al3)]; S2L = [2 3]; V2x = [0 0]; V2s = [0 1*tand(al2)]; W2s = [0 1*tand(b2)]; U2x = [3 3]; U2y = [1*tand(b2) 1*tand(al2)]; S3L = [4 5]; V3x = [0 0]; V3r = [0 1*tand(al3)]; W3r = [0 1*tand(b3)]; U3x = [5 5]; U3y = [1*tand(b3) 1*tand(al3)]; plot(S1L,V1x,'k',S1L,V1s,'r',... S2L,V2x,'k',S2L,V2s,'r',S2L,W2s,'b',U2x,U2y,'g',... S3L,V3x,'k',S3L,V3r,'r',S3L,W3r,'b',U3x,U3y,'g',...... 'LineWidth',2,'MarkerSize',10),...…arrow_forward
- USE MATLAB ONLY provide typed code solve for velocity triangle and dont provide copied answer Turbomachienery . GIven: vx = 185 m/s, flow angle = 60 degrees, R = 0.5, U = 150 m/s, b2 = -a3, a2 = -b3 Find: velocity triangle , a. magnitude of abs vel leaving rotor (m/s) b. flow absolute angles (a1, a2, a3) 3. flow rel angles (b2, b3) d. specific work done e. use code to draw vel. diagram Use this code for plot % plots Velocity Tri. in Ch4 function plotveltri(al1,al2,al3,b2,b3) S1L = [0 1]; V1x = [0 0]; V1s = [0 1*tand(al3)]; S2L = [2 3]; V2x = [0 0]; V2s = [0 1*tand(al2)]; W2s = [0 1*tand(b2)]; U2x = [3 3]; U2y = [1*tand(b2) 1*tand(al2)]; S3L = [4 5]; V3x = [0 0]; V3r = [0 1*tand(al3)]; W3r = [0 1*tand(b3)]; U3x = [5 5]; U3y = [1*tand(b3) 1*tand(al3)]; plot(S1L,V1x,'k',S1L,V1s,'r',... S2L,V2x,'k',S2L,V2s,'r',S2L,W2s,'b',U2x,U2y,'g',... S3L,V3x,'k',S3L,V3r,'r',S3L,W3r,'b',U3x,U3y,'g',...... 'LineWidth',2,'MarkerSize',10),... axis([-1 6 -4 4]), ...…arrow_forwardThe answer should equal to 1157. Please sent me the solution. Thank you!arrow_forwardBONUS: If the volume of the 8cm x 6.5cm x 6cm Block of Aluminum was 312cm3 before machining, find how much material was removed when the fixture below was machined. +2 2.00 cm 6.00 cm 2.50 cm 6.50 cm 1.00 cm 2.50 cm 11.00 cm 8.00 cm 30 CP 9411 FL.4) (m² 1157 Area of triangle = 1/2*B*H Area of circle = лR² Circumference of a circle = 2πR 6.00 cm 6.50 cm 1.50 cm Radius 1.50 cm 1.00 cmarrow_forward
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