
(a)
Interpretation:
From the given Newman projection formulas of tartaric acid, same representations has to be identified.
Concept Introduction:
Priority rules:
- Priorities based on
atomic number
- When priority cannot be assigned on the basis of the atoms bonded directly to the chiral center
- Atoms participating in a double or triple bond are considered to be bonded to an equivalent number of phantom atoms.
For example,
- Priority assignment is made at the first point of difference between groups (should not be based on the larger group).
(b)
Interpretation:
From the given Newman projection formulas of tartaric acid, enantiomeric representations has to be identified.
Concept Introduction:
Enantiomers:
Stereoisomers having nonsuperposable mirror image relationship are called as enantiomers.
(c)
Interpretation:
From the given Newman projection formulas of tartaric acid, meso representation has to be identified.
Concept Introduction:
Meso compound:
It is an achiral compound having two or more chiral centers that also has chiral isomers.
(d)
Interpretation:
From the given Newman projection formulas of tartaric acid, diastereomers has to be identified.
Concept Introduction:
Diastereomers:
Stereoisomers that are not having nonsuperposable mirror image relationship are called as diastereomers.

Trending nowThis is a popular solution!

Chapter 3 Solutions
Organic Chemistry, Loose-leaf Version
- Q5: Label each chiral carbon in the following molecules as R or S. Make sure the stereocenter to which each of your R/S assignments belong is perfectly clear to the grader. (8pts) R OCH 3 CI H S 2pts for each R/S HO R H !!! I OH CI HN CI R Harrow_forwardCalculate the proton and carbon chemical shifts for this structurearrow_forwardA. B. b. Now consider the two bicyclic molecules A. and B. Note that A. is a dianion and B. is a neutral molecule. One of these molecules is a highly reactive compound first characterized in frozen noble gas matrices, that self-reacts rapidly at temperatures above liquid nitrogen temperature. The other compound was isolated at room temperature in the early 1960s, and is a stable ligand used in organometallic chemistry. Which molecule is the more stable molecule, and why?arrow_forward
- A mixture of C7H12O2, C9H9OCl, biphenyl and acetone was put together in a gas chromatography tube. Please decide from the GC resutls which correspond to the peak for C7,C9 and biphenyl and explain the reasoning based on GC results. Eliminate unnecessary peaks from Gas Chromatography results.arrow_forwardIs the molecule chiral, meso, or achiral? CI .CH3 H₂C CIarrow_forwardPLEASE HELP ! URGENT!arrow_forward
- Identify priority of the substituents: CH3arrow_forwardHow many chiral carbons are in the molecule? OH F CI Brarrow_forwardA mixture of three compounds Phen-A, Acet-B and Rin-C was analyzed using TLC with 1:9 ethanol: hexane as the mobile phase. The TLC plate showed three spots of R, 0.1 and 0.2 and 0.3. Which of the three compounds (Phen-A; Acet-B or Rin-C) would have the highest (Blank 1), middle (Blank 2) and lowest (Blank 3) spot respectively? 0 CH: 0 CH, 0 H.C OH H.CN OH Acet-B Rin-C phen-A A A <arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning
