Pearson eText for College Algebra and Trigonometry -- Instant Access (Pearson+)
4th Edition
ISBN: 9780137399048
Author: J. S. Ratti, Marcus McWaters
Publisher: PEARSON+
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Chapter 3.3, Problem 39E
To determine
Use the Factor Theorem to show that the linear polynomial is a factor of the second polynomial. Check your answer by synthetic division..
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I want a mathematical relationship with all the details, not explanations and definitions
4 sinx cos2x+4 cos x sin2x-1=0
For the matrix A, find (if possible) a nonsingular matrix P such that P-1AP is diagonal. (If not possible, enter IMPOSSIBLE.)
6 -2
-[47]
A =
-3 1
P =
Verify that P-1AP is a diagonal matrix with the eigenvalues on the main diagonal.
P-1AP =
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- (e) Without using a membership table, show that (A N B) U (A N B) = A. State all the rules used.arrow_forwardThe function r has vertical asymptotes x =____________ (smaller value) and x = __________ (larger value)arrow_forwardProblem 1. 1.1. In each of the below, find a complete list of subgroups of the group G and write down their orders. a) The group G = Z/48Z b) The group G of rotations in D14. c) The group G = Z13 of 13-th roots of unity in C. 1.2. Find all elements x of the group G from 1.1 b) which generate G. 1.3. Let H = [[20]) ℃ Z/48Z. Using only order, determine which of the subgroups from your solution to 1.1 a) H coincides with.arrow_forward
- my teacher told me the answer was 4a⁷b⁶ because of the product of a power how can I tell the truth us there any laws in math please provide the law to correct her tyarrow_forwarda=1 b=41)Find the vector and parametric scalar equations of the line L. Show that Q does not lieon L. 2)Without performing any numerical calculations, express d in terms of sin(θ) and |P Q| andhence show that d = |P Q × v(v with a hat)|. Proceed to use your points P and Q and the vector v(hat) to find d. 3)Find the point R such that PR =(P Q · v(hat)/|v(hat)| 2⃗ ) * v(hat). Confirm that R lies on the line L. Interpret the vector P R. Finally, verify that d = |RQ|.arrow_forwardDirections: Use your knowledge of properties of quadratic equations to answer each question. Show all work and label your answers with appropriate units. Round any decimals to the nearest hundredths place. 1. The hypotenuse of a right triangle is 5 centimeters longer than one leg and 10 centimeters longer than the other leg. What are the dimensions of the triangle? 2. The profit of a cell phone manufacturer is found by the function y = -2x²+ 108x+75, where x is the price of the cell phone. At what price should the manufacturer sell the phone to maximize its profits? What will the maximum profit be? 3. A farmer wants to build a fence around a rectangular area of his farm with one side of the region against his barn. He has 76 feet of fencing to use for the three remaining sides. What dimensions will make the largest area for the region? 4. A 13-foot ladder is leaning against a building, forming a right triangle. The height where the ladder touches the building is 7 feet more than the…arrow_forward
- Consider the linear system: x12x2ax3 - 3x1 + x2 3x3 -3x14x2+7x3 a) For what value of a we can not solve the above system using Cramer's Rule? a b) If we take a 3 what will be the value of x₁? x1 = == 4. =-7 ==arrow_forwardIf u and v are any elements in vector space V and u v is not in V then V is not closed under the operation . ○ True ○ Falsearrow_forwardConsider the linear system: x1 + 2x2 + 3x3 3x1 + 2x2 + x3 = 17 = 11 x1 - 5x2 + x3 =-5 Let A be the coefficient matrix of the given system and using Cramer's Rule x = • x1 = = det(A2) = ÷ det(Ai) det(A)arrow_forward
- The linear system can be solved by Cramer's Rule. ○ True ○ False 2x14x26x3 = 2, x1 + 2x3 = 0, 2x13x2 x3 = −5arrow_forwardConsider the linear system: 2x1 +7x2 = -21 -x1-3x2 = = 14 Which one of the following gives the value of x₁ using Cramer's rule? Select one: 21 7 14 -3 x1 = 2 7 -1 -3 -21 7 14 -3 x1 2 7 1 -3 O None of these. -21 -1 14 x1 = 2 7 -1 -3 -21 -1 14 x1 = 2 7 1 -3arrow_forwardWrite the augmented matrix of the system -70y +4z 6 20x +60z -48 -3x -4y-48z -12arrow_forward
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