
(a)
Interpretation:
A balanced chemical equation for a reaction between sodium and water to form hydrogen gas and the solution of sodium hydroxide is to be written.
Concept introduction:
A balanced chemical equation obeyed the law of conservation of mass since the total mass of reactants and products are equal in a balanced chemical equation.
Following are the steps to write a balanced chemical equation.
Step 1: Translate the chemical statement into a skeleton equation. The reactants are the chemical substances that undergo a change, thus, write the reactants on the left side of the yield arrow. The products are the chemical substances that are produced during the chemical change, thus, write the products on the right side of the yield arrow. Put a blank before each formula while beginning the balancing process.
Step 2: Identify the most complex substance and choose an element such that the element must be present only in one reactant and one product. Place the stoichiometric coefficient before the element/elements such that the number of atoms of that element(s) is the same on both sides.
Step 3: Balance the remaining atoms by placing the
Step 4: In a balanced
Step 5: Check whether the chemical equation is balanced or not by counting the number of atoms of each element on both sides.
Step 6: Specify the
(b)
Interpretation:
A balanced chemical equation for a reaction between aqueous nitric acid and calcium carbonate to form carbon dioxide, water, and an aqueous solution of calcium nitrate is to be written.
Concept introduction:
A balanced chemical equation obeyed the law of conservation of mass since the total mass of reactants and products are equal in a balanced chemical equation.
Following are the steps to write a balanced chemical equation.
Step 1: Translate the chemical statement into a skeleton equation. The reactants are the chemical substances that undergo a change, thus, write the reactants on the left side of the yield arrow. The products are the chemical substances that are produced during the chemical change, thus, write the products on the right side of the yield arrow. Put a blank before each formula while beginning the balancing process.
Step 2: Identify the most complex substance and choose an element such that the element must be present only in one reactant and one product. Place the stoichiometric coefficient before the element/elements such that the number of atoms of that element(s) is the same on both sides.
Step 3: Balance the remaining atoms by placing the stoichiometric coefficients before the element/elements such that the number of atoms of that element(s) is the same on both sides. Identify the least complex substance and end with it.
Step 4: In a balanced chemical reaction, the smallest whole number coefficients are most preferred. Hence, adjusting the coefficients in such a way that the smallest whole number coefficients are obtained for each element.
Step 5: Check whether the chemical equation is balanced or not by counting the number of atoms of each element on both sides.
Step 6: Specify the states of matter of each chemical substance present in the balanced chemical equation. The table for the abbreviations used for each state is as follows:
(c)
Interpretation:
A balanced chemical equation for a reaction between phosphorous trichloride and hydrogen fluoride to form phosphorous trifluoride and hydrogen chloride is to be written.
Concept introduction:
A balanced chemical equation obeyed the law of conservation of mass since the total mass of reactants and products are equal in a balanced chemical equation.
Following are the steps to write a balanced chemical equation.
Step 1: Translate the chemical statement into a skeleton equation. The reactants are the chemical substances that undergo a change, thus, write the reactants on the left side of the yield arrow. The products are the chemical substances that are produced during the chemical change, thus, write the products on the right side of the yield arrow. Put a blank before each formula while beginning the balancing process.
Step 2: Identify the most complex substance and choose an element such that the element must be present only in one reactant and one product. Place the stoichiometric coefficient before the element/elements such that the number of atoms of that element(s) is the same on both sides.
Step 3: Balance the remaining atoms by placing the stoichiometric coefficients before the element/elements such that the number of atoms of that element(s) is the same on both sides. Identify the least complex substance and end with it.
Step 4: In a balanced chemical reaction, the smallest whole number coefficients are most preferred. Hence, adjusting the coefficients in such a way that the smallest whole number coefficients are obtained for each element.
Step 5: Check whether the chemical equation is balanced or not by counting the number of atoms of each element on both sides.
Step 6: Specify the states of matter of each chemical substance present in the balanced chemical equation. The table for the abbreviations used for each state is as follows:

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Chapter 3 Solutions
CONNECT ACCESS CARD FOR CHEMISTRY: MOLECULAR NATURE OF MATTER AND CHANGE
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- 9. Which one of the following substituents is the worst leaving group inan SN2 reaction? A. -NH2; B. -OH; C. –F; D. NH3; E. H2O Please include all steps. Thanks!arrow_forwardUsing the general properties of equilibrium constants At a certain temperature, the equilibrium constant K for the following reaction is 2.5 × 105: CO(g) + H2O(g) CO2(g) + H2(g) Use this information to complete the following table. Suppose a 7.0 L reaction vessel is filled with 1.7 mol of CO and 1.7 mol of H2O. What can you say about the composition of the mixture in the vessel at equilibrium? What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. CO2(9)+H2(g) CO(g)+H₂O(g) What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. 3 CO(g)+3H2O(g) = 3 CO2(g)+3H2(g) There will be very little CO and H2O. x10 There will be very little CO2 and H2. 000 Neither of the above is true. K = ☐ K = ☐ 18 Ararrow_forward8. When ethane thiol is treated with hydrogen peroxide the product is___.A. ethane disulfide; B. diethyl sulfide; C. ethane sulfoxide; D. ethanesulfate; E. ethyl mercaptan. Please include all steps. Thanks!arrow_forward
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