Chapter 3.3, Problem 28E

Repeat Exercise 27 with ${\text{b}}_{\text{1}}=\left[\begin{array}{c}4\\ -7\end{array}\right]$, ${\text{b}}_{\text{2}}=\left[\begin{array}{c}0\\ 1\end{array}\right]$, and $A=\left[\begin{array}{cc}5& 2\\ 1& 1\end{array}\right]$.