Building Java Programs: A Back To Basics Approach, Loose Leaf Edition (5th Edition)
5th Edition
ISBN: 9780135472118
Author: Stuart Reges, Marty Stepp
Publisher: PEARSON
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Expert Solution & Answer
Chapter 3.3, Problem 20SCP
a.
Explanation of Solution
Result of “str1.length()”:
- The function “length()”is used to return the number of characters in the given string.
- The variable “str1” is assigned the string value “Q.E...
b.
Explanation of Solution
Result of “str2.length()”:
- The function “length()”is used to return the number of characters in the given string.
- The variable “str2” is assigned the string value “Arcturan Megadonkey”...
c.
Explanation of Solution
Result of “str1.toUpperCase()”:
- The function “toUpperCase()”is used to return the string with all uppercase letters...
d.
Explanation of Solution
Result of “str2.toUpperCase()”:
- The function “toUpperCase()”is used to return the string with all uppercase letters...
e.
Explanation of Solution
Result of “str1.substring(2,4)”:
- The function “substring()”is used to return the substring for the specified index range.
- The variable “str1” is assigned the string value “Q.E.D.”.
- The starting index of the string is “0”...
f.
Explanation of Solution
Result of “str2.substring(10,14)”:
- The function “substring()”is used to return the substring for the specified index range.
- The variable “str2” is assigned the string value “Arcturan Megadonkey”.
- The starting index of the string is “0”...
g.
Explanation of Solution
Result of “str1.indexOf(“D”)”:
- The function “indexOf()”is used to return the index of the first occurrences of the given character “D”.
- The variable “str1” is assigned the string value “Q.E.D.”.
- The starting index of the string is “0”...
h.
Explanation of Solution
Result of “str1.indexOf(“.”)”:
- The function “indexOf()”is used to return the index of the first occurrences of the given character “.”.
- The variable “str1” is assigned the string value “Q.E.D.”.
- The starting index of the string is “0”...
i.
Explanation of Solution
Result of “str2.indexOf(“donkey”)”:
- The function “indexOf()”is used to return the index of the first occurrences of the given strinf “donkey”.
- The variable “str2” is assigned the string value “Arcturan Megadonkey”.
- The starting index of the string is “0”...
j.
Explanation of Solution
Result of “str3.indexOf(“X”)”:
- The function “indexOf()”is used to return the index of the first occurrences of the given character “X”.
- The variable “str3” is assigned the string value “Sirius Cybernetics Corporation”.
- The starting index of the string is “0”...
k.
Explanation of Solution
Result of “str2 + str3 . charAt(17)”:
- The function “charAt()”is used to return the character at the given index.
- The variable “str2” is assigned the string value “Arcturan Megadonkey”.
- The variable “str3” is assigned the string value “Sirius Cybernetics Corporation”...
l.
Explanation of Solution
Result of “str3.substring(9,str3.index0f("e"))”:
- The function “indexOf()” is used to return the index of the first occurrences of the given character.
- The variable “str3” is assigned the string value “Sirius Cybernetics Corporation”.
- The function “indexOf(“e”)” returns the index of first occurrence of the character “e”. Hence the index is “10”...
m.
Explanation of Solution
Result of “str3.substring(7,12)”:
- The function “substring()” is used to return the substring for the specified index range.
- The variable “str3” is assigned the string value “Sirius Cybernetics Corporation”.
- The starting index of the string is “0”...
n.
Explanation of Solution
Result of “str2.toLowerCase().substring(9,13) + str3. substring(18,str3.length() - 7)”:
- The function “substring()” is used to return the substring for the specified index range.
- The function “toLowerCase()” is used to return the string with all lowercase letters.
- The function “length()”is used to return the number of characters in the given string.
- The variable “str3” is assigned the string value “Sirius Cybernetics Corporation”.
- The variable “str2” is assigned the string value “Arcturan Megadonkey”.
- The starting index of the string is “0”.
- The expression “str2.toLowerCase()” returns the string “arcturan megadonkey”.
- The given expression “str2...
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Chapter 3 Solutions
Building Java Programs: A Back To Basics Approach, Loose Leaf Edition (5th Edition)
Ch. 3.1 - Which of the following is the correct syntax for a...Ch. 3.1 - Prob. 2SCPCh. 3.1 - Prob. 3SCPCh. 3.1 - Prob. 4SCPCh. 3.1 - Prob. 5SCPCh. 3.1 - What is the output of the following...Ch. 3.1 - Prob. 7SCPCh. 3.1 - Prob. 8SCPCh. 3.1 - Prob. 9SCPCh. 3.1 -
Write a method called printStrings that accepts a...
Ch. 3.1 - Prob. 11SCPCh. 3.2 -
What is wrong with the following program?
public...Ch. 3.2 -
Evaluate the following expressions:
a Math.abs...Ch. 3.2 -
What output is produced by the following...Ch. 3.2 - Prob. 15SCPCh. 3.2 - Prob. 16SCPCh. 3.2 -
Write a method called countQuarters that takes an...Ch. 3.3 - Prob. 18SCPCh. 3.3 - Prob. 19SCPCh. 3.3 - Prob. 20SCPCh. 3.3 - Prob. 21SCPCh. 3.3 -
Consider the following code fragment:
Scanner...Ch. 3.3 - Prob. 23SCPCh. 3.3 - Prob. 24SCPCh. 3.3 - Prob. 25SCPCh. 3 - Prob. 1ECh. 3 -
Write a method called printPowersOf2 that accepts...Ch. 3 -
Write a method called printPowersOfN that accepts...Ch. 3 - Prob. 4ECh. 3 - Prob. 5ECh. 3 - Prob. 6ECh. 3 -
Write a variation of the largestAbsVal method...Ch. 3 -
Write a method called quadratic that solves...Ch. 3 -
Write a method called lastDigit that returns the...Ch. 3 - Prob. 10ECh. 3 - Prob. 11ECh. 3 - Prob. 12ECh. 3 - Prob. 13ECh. 3 - Prob. 14ECh. 3 - Prob. 15ECh. 3 - Prob. 16ECh. 3 - Prob. 17ECh. 3 -
Write a method called vertical that accepts a...Ch. 3 - Prob. 19ECh. 3 - Prob. 20ECh. 3 - Prob. 21ECh. 3 - Prob. 22ECh. 3 - Write a method called printIndexed that accepts a...Ch. 3 - Write a program that produces images of Christmas...Ch. 3 - Prob. 2PPCh. 3 - Prob. 3PPCh. 3 - Prob. 4PPCh. 3 - Prob. 5PPCh. 3 - Write a program that produces calendars as output....
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