Calculus
5th Edition
ISBN: 9781429241861
Author: Laura Taalman, Peter Kohn
Publisher: W. H. Freeman
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Chapter 3.3, Problem 1C
(a)
To determine
To find:whether the given statement is true or false.
(b)
To determine
To find:whether the given statement is true or false.
(c)
To determine
To find:whether the given statement is true or false.
(d)
To determine
To find:whether the given statement is true or false.
(e)
To determine
To find:whether the given statement is true or false.
(f)
To determine
To find:whether the given statement is true or false.
(g)
To determine
To find:whether the given statement is true or false.
(h)
To determine
To find:whether the given statement is true or false.
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Use the information in the following table to find h' (a) at the given value for a.
x|f(x) g(x) f'(x) g(x)
0
0
0
4
3
1
4
4
3
0
2
7
1
2
7
3
3
1
2
9
4
0
4
5
7
h(x) = f(g(x)); a = 0
h' (0) =
Use the information in the following table to find h' (a) at the given value for a.
x f(x) g(x) f'(x) g'(x)
0
0
3
2
1
1
0
0
2
0
2
43
22
4
3
3
2
3
1
1
4
1
2
0
4
2
h(x) = (1/(2) ²;
9(x)
h' (3)=
=
; a=3
The position of a moving hockey puck after t seconds is s(t) = tan
a. Find the velocity of the hockey puck at any time t.
v(t)
=====
b. Find the acceleration of the puck at any time t.
-1
a (t)
=
(t) where s is in meters.
c. Evaluate v(t) and a (t) for t = 1, 4, and 5 seconds. Round to 4 decimal places, if necessary.
v (1)
v (4)
v (5)
a (1)
=
=
=
=
a (4) =
a (5) =
d. What conclusion can be drawn from the results in the previous part?
○ The hockey puck is decelerating/slowing down at 1, 4, and 5 seconds
○ The hockey puck has a constant velocity/speed at 1, 4, and 5 seconds
○ The hockey puck is accelerating/speeding up at 1, 4, and 5 seconds
Chapter 3 Solutions
Calculus
Ch. 3.1 - Prob. 1TBCh. 3.1 - Prob. 0CCh. 3.1 - Prob. 1CCh. 3.1 - Prob. 2CCh. 3.1 - Prob. 3CCh. 3.1 - Prob. 4CCh. 3.1 - Prob. 5CCh. 3.1 - Prob. 6CCh. 3.1 - Prob. 7CCh. 3.1 - Prob. 8C
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- f'(x)arrow_forwardA body of mass m at the top of a 100 m high tower is thrown vertically upward with an initial velocity of 10 m/s. Assume that the air resistance FD acting on the body is proportional to the velocity V, so that FD=kV. Taking g = 9.75 m/s2 and k/m = 5 s, determine: a) what height the body will reach at the top of the tower, b) how long it will take the body to touch the ground, and c) the velocity of the body when it touches the ground.arrow_forwardA chemical reaction involving the interaction of two substances A and B to form a new compound X is called a second order reaction. In such cases it is observed that the rate of reaction (or the rate at which the new compound is formed) is proportional to the product of the remaining amounts of the two original substances. If a molecule of A and a molecule of B combine to form a molecule of X (i.e., the reaction equation is A + B ⮕ X), then the differential equation describing this specific reaction can be expressed as: dx/dt = k(a-x)(b-x) where k is a positive constant, a and b are the initial concentrations of the reactants A and B, respectively, and x(t) is the concentration of the new compound at any time t. Assuming that no amount of compound X is present at the start, obtain a relationship for x(t). What happens when t ⮕∞?arrow_forwardConsider a body of mass m dropped from rest at t = 0. The body falls under the influence of gravity, and the air resistance FD opposing the motion is assumed to be proportional to the square of the velocity, so that FD = kV2. Call x the vertical distance and take the positive direction of the x-axis downward, with origin at the initial position of the body. Obtain relationships for the velocity and position of the body as a function of time t.arrow_forwardAssuming that the rate of change of the price P of a certain commodity is proportional to the difference between demand D and supply S at any time t, the differential equations describing the price fluctuations with respect to time can be expressed as: dP/dt = k(D - s) where k is the proportionality constant whose value depends on the specific commodity. Solve the above differential equation by expressing supply and demand as simply linear functions of price in the form S = aP - b and D = e - fParrow_forwardFind the area of the surface obtained by rotating the circle x² + y² = r² about the line y = r.arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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