Pre-Algebra Student Edition
Pre-Algebra Student Edition
1st Edition
ISBN: 9780078957734
Author: Glencoe/McGraw-Hill
Publisher: MCG
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Concept explainers

Unitary Method
The word “unitary” comes from the word “unit”, which means a single and complete entity. In this method, we find the value of a unit product from the given number of products, and then we solve for the other number of products.
Speed, Time, and Distance
Imagine you and 3 of your friends are planning to go to the playground at 6 in the evening. Your house is one mile away from the playground and one of your friends named Jim must start at 5 pm to reach the playground by walk. The other two friends are 3 …
Profit and Loss
The amount earned or lost on the sale of one or more items is referred to as the profit or loss on that item.
Units and Measurements
Measurements and comparisons are the foundation of science and engineering. We, therefore, need rules that tell us how things are measured and compared. For these measurements and comparisons, we perform certain experiments, and we will need the experime…
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Question
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Chapter 3.2, Problem 64STP

a)

To determine

To convert: The decimal numbers of the given table in fractional form.

a)

Expert Solution
Check Mark

Answer to Problem 64STP

Each decimal in simplest fraction form is as follows:

  0.40=25,     0.18=950,  0.36=925,    0.04=125,    0.02=150

Explanation of Solution

Given information: A table that shows the method of transportations and total portion of students (in decimal form), using these methods.

Concept used: Given decimal values are written in fraction form by removing its decimal sign and dividing them by 100 and then by converting them in simplest form. Further by comparing the numerators, with denominator 100, given decimal numbers are put from least to greatest.

Calculation: Change decimal values in simple fraction form as shown below:

0.40=25,     0.18=950,  0.36=925,    0.04=125,    0.02=150

Conclusion: By above calculation, it is cleared that each decimal in simplest fraction form is as follows: 0.40=25,     0.18=950,  0.36=925,    0.04=125,    0.02=150 .

b)

To determine

To list: The methods of transportation in order from least to greatest.

b)

Expert Solution
Check Mark

Answer to Problem 64STP

List of methods of transportations from least to greatest is:

Others, bicycle, walk, car, bus

Explanation of Solution

Given information: A table that shows the method of transportations and total portion of students (in decimal form), using these methods.

Concept used: First write the given decimal numbers in ascending order and then put methods of transportation, represented by these number in the same order from least to greatest.

Calculation: Write given decimal number in ascending order, from least to greatest as: 0.02<0.04<0.18<0.36<0.40

Conclusion: By above sequence, it is cleared that methods of transportations representing above decimal number, in ascending order are:

Others, bicycle, walk, car, bus

c)

To determine

To find: The methods of transportation that is used by most students to get to school.

c)

Expert Solution
Check Mark

Answer to Problem 64STP

Bus is used by most of the students to get to school.

Explanation of Solution

Given information: A table that shows the method of transportations and total portion of students (in decimal form), using these methods.

Concept used: First write the given decimal numbers in ascending order and then put methods of transportation, represented by these number in the same order from least to greatest.

Calculation: Write given decimal numbers in ascending order as: 0.02<0.04<0.18<0.36<0.40

Conclusion: By above sequence, it is cleared that greatest number is 0.4 that represents method of transportation as BUS, so bus is mostly used by the students to get the school.

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Chapter 3.2, Problem 63STP
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Chapter 3.2, Problem 65SR

Chapter 3 Solutions

Pre-Algebra Student Edition

Ch. 3.1 - Prob. 1AGPCh. 3.1 - Prob. 1BGPCh. 3.1 - Prob. 2AGPCh. 3.1 - Prob. 2BGPCh. 3.1 - Prob. 3GPCh. 3.1 - Prob. 4AGPCh. 3.1 - Prob. 4BGPCh. 3.1 - Prob. 5GPCh. 3.1 - Prob. 1CYUCh. 3.1 - Prob. 2CYU
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Prob. 3CGPCh. 3.5 - Prob. 4GPCh. 3.5 - Prob. 5GPCh. 3.5 - Prob. 6AGPCh. 3.5 - Prob. 6bGPCh. 3.5 - Prob. 6CGPCh. 3.5 - Prob. 1CYUCh. 3.5 - Prob. 2CYUCh. 3.5 - Prob. 3CYUCh. 3.5 - Prob. 4CYUCh. 3.5 - Prob. 5CYUCh. 3.5 - Prob. 6CYUCh. 3.5 - Prob. 7CYUCh. 3.5 - Prob. 8CYUCh. 3.5 - Prob. 9CYUCh. 3.5 - Prob. 10CYUCh. 3.5 - Prob. 11CYUCh. 3.5 - Prob. 12CYUCh. 3.5 - Prob. 13CYUCh. 3.5 - Prob. 14PPSCh. 3.5 - Prob. 15PPSCh. 3.5 - Prob. 16PPSCh. 3.5 - Prob. 17PPSCh. 3.5 - Prob. 18PPSCh. 3.5 - Prob. 19PPSCh. 3.5 - Prob. 20PPSCh. 3.5 - Prob. 21PPSCh. 3.5 - Prob. 22PPSCh. 3.5 - Prob. 23PPSCh. 3.5 - Prob. 24PPSCh. 3.5 - Prob. 25PPSCh. 3.5 - Prob. 26PPSCh. 3.5 - Prob. 27PPSCh. 3.5 - Prob. 28PPSCh. 3.5 - Prob. 29PPSCh. 3.5 - Prob. 30PPSCh. 3.5 - Prob. 31PPSCh. 3.5 - Prob. 32PPSCh. 3.5 - Prob. 33PPSCh. 3.5 - Prob. 34PPSCh. 3.5 - Prob. 35PPSCh. 3.5 - Prob. 36PPSCh. 3.5 - Prob. 37PPSCh. 3.5 - Prob. 38PPSCh. 3.5 - Prob. 39PPSCh. 3.5 - Prob. 40PPSCh. 3.5 - Prob. 41PPSCh. 3.5 - Prob. 42PPSCh. 3.5 - Prob. 43HPCh. 3.5 - 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Prob. 1QCCh. 3 - Prob. 2QCCh. 3 - Prob. 3QCCh. 3 - Prob. 4QCCh. 3 - Prob. 5QCCh. 3 - Prob. 6QCCh. 3 - Prob. 7QCCh. 3 - Prob. 8QCCh. 3 - Prob. 9QCCh. 3 - Prob. 10QCCh. 3 - Prob. 11QCCh. 3 - Prob. 12QCCh. 3 - Prob. 13QCCh. 3 - Prob. 14QCCh. 3 - Prob. 15QCCh. 3 - Prob. 16QCCh. 3 - Prob. 17QCCh. 3 - Prob. 18QCCh. 3 - Prob. 19QCCh. 3 - Prob. 20QCCh. 3 - Prob. 21QCCh. 3 - Prob. 1MCQCh. 3 - Prob. 2MCQCh. 3 - Prob. 3MCQCh. 3 - Prob. 4MCQCh. 3 - Prob. 5MCQCh. 3 - Prob. 6MCQCh. 3 - Prob. 7MCQCh. 3 - Prob. 8MCQCh. 3 - Prob. 9MCQCh. 3 - Prob. 10MCQCh. 3 - Prob. 11MCQCh. 3 - Prob. 12MCQCh. 3 - Prob. 13MCQCh. 3 - Prob. 14MCQCh. 3 - Prob. 15MCQCh. 3 - Prob. 16MCQCh. 3 - Prob. 17MCQCh. 3 - Prob. 18MCQCh. 3 - Prob. 19MCQCh. 3 - Prob. 20MCQCh. 3 - Prob. 21MCQCh. 3 - Prob. 22MCQCh. 3 - Prob. 23MCQCh. 3 - Prob. 24MCQCh. 3 - Prob. 25MCQCh. 3 - Prob. 26MCQCh. 3 - Prob. 27MCQCh. 3 - Prob. 28MCQCh. 3 - Prob. 29MCQCh. 3 - Prob. 30MCQCh. 3 - Prob. 1SGRCh. 3 - Prob. 2SGRCh. 3 - Prob. 3SGRCh. 3 - Prob. 4SGRCh. 3 - Prob. 5SGRCh. 3 - Prob. 6SGRCh. 3 - Prob. 7SGRCh. 3 - Prob. 8SGRCh. 3 - Prob. 9SGRCh. 3 - Prob. 10SGRCh. 3 - Prob. 11SGRCh. 3 - Prob. 12SGRCh. 3 - Prob. 13SGRCh. 3 - Prob. 14SGRCh. 3 - Prob. 15SGRCh. 3 - Prob. 16SGRCh. 3 - Prob. 17SGRCh. 3 - Prob. 18SGRCh. 3 - Prob. 19SGRCh. 3 - Prob. 20SGRCh. 3 - Prob. 21SGRCh. 3 - Prob. 22SGRCh. 3 - Prob. 23SGRCh. 3 - Prob. 24SGRCh. 3 - Prob. 25SGRCh. 3 - Prob. 26SGRCh. 3 - Prob. 27SGRCh. 3 - Prob. 28SGRCh. 3 - Prob. 29SGRCh. 3 - Prob. 30SGRCh. 3 - Prob. 31SGRCh. 3 - Prob. 32SGRCh. 3 - Prob. 33SGRCh. 3 - Prob. 34SGRCh. 3 - Prob. 35SGRCh. 3 - Prob. 36SGRCh. 3 - Prob. 37SGRCh. 3 - Prob. 38SGRCh. 3 - Prob. 39SGRCh. 3 - Prob. 40SGRCh. 3 - Prob. 41SGRCh. 3 - Prob. 42SGRCh. 3 - Prob. 43SGRCh. 3 - Prob. 44SGRCh. 3 - Prob. 45SGRCh. 3 - Prob. 46SGRCh. 3 - Prob. 47SGRCh. 3 - Prob. 48SGRCh. 3 - Prob. 49SGRCh. 3 - Prob. 50SGRCh. 3 - Prob. 51SGRCh. 3 - Prob. 52SGRCh. 3 - Prob. 53SGRCh. 3 - Prob. 54SGRCh. 3 - Prob. 55SGRCh. 3 - Prob. 56SGRCh. 3 - Prob. 57SGRCh. 3 - 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Prob. 14STP

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Precalculus

In Exercises 1–8, integrate the given function over the given surface. 2. Circular cylinder G(x, y, z) = z, ove...

University Calculus: Early Transcendentals (4th Edition)

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