To verify: The solution to the wave equation is E y ( x , t ) = E max e − k C x cos ( k C x − ω t ) by substituting E y ( x , t ) in ∂ 2 E y ( x , t ) ∂ x 2 = μ ρ ∂ E y ( x , t ) ∂ t

Question

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Answer 1

Question

Chapter 32, Problem 56E

(a)

To determine

To verify: The solution to the wave equation is Ey(x,t)=Emaxe−kCxcos(kCx−ωt) by substituting Ey(x,t) in ∂2Ey(x,t)∂x2=μρ ∂Ey(x,t)∂t

(b)

To determine

To explain: Why the electric field decreases in amplitude as wave propagates.

(c)

To determine

To show: The electric field amplitude decreases by a factor of 1e in a distance 1kC=2ρωμ and to calculate that distance for a radio wave with frequency f=1.0 MHz in copper.

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Answer 2

Question

Chapter 32, Problem 56E

(a)

To determine

To verify: The solution to the wave equation is Ey(x,t)=Emaxe−kCxcos(kCx−ωt) by substituting Ey(x,t) in ∂2Ey(x,t)∂x2=μρ ∂Ey(x,t)∂t

(b)

To determine

To explain: Why the electric field decreases in amplitude as wave propagates.

(c)

To determine

To show: The electric field amplitude decreases by a factor of 1e in a distance 1kC=2ρωμ and to calculate that distance for a radio wave with frequency f=1.0 MHz in copper.

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Answer 3

Question

Chapter 32, Problem 56E

(a)

To determine

To verify: The solution to the wave equation is Ey(x,t)=Emaxe−kCxcos(kCx−ωt) by substituting Ey(x,t) in ∂2Ey(x,t)∂x2=μρ ∂Ey(x,t)∂t

(b)

To determine

To explain: Why the electric field decreases in amplitude as wave propagates.

(c)

To determine

To show: The electric field amplitude decreases by a factor of 1e in a distance 1kC=2ρωμ and to calculate that distance for a radio wave with frequency f=1.0 MHz in copper.

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Answer 4

Question

Chapter 32, Problem 56E

(a)

To determine

To verify: The solution to the wave equation is Ey(x,t)=Emaxe−kCxcos(kCx−ωt) by substituting Ey(x,t) in ∂2Ey(x,t)∂x2=μρ ∂Ey(x,t)∂t

(b)

To determine

To explain: Why the electric field decreases in amplitude as wave propagates.

(c)

To determine

To show: The electric field amplitude decreases by a factor of 1e in a distance 1kC=2ρωμ and to calculate that distance for a radio wave with frequency f=1.0 MHz in copper.

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Answer 5

Chapter 32, Problem 56E

(a)

To determine

To verify: The solution to the wave equation is Ey(x,t)=Emaxe−kCxcos(kCx−ωt) by substituting Ey(x,t) in ∂2Ey(x,t)∂x2=μρ ∂Ey(x,t)∂t

(b)

To determine

To explain: Why the electric field decreases in amplitude as wave propagates.

(c)

To determine

To show: The electric field amplitude decreases by a factor of 1e in a distance 1kC=2ρωμ and to calculate that distance for a radio wave with frequency f=1.0 MHz in copper.

Answer 6

Chapter 32, Problem 56E

(a)

To determine

To verify: The solution to the wave equation is Ey(x,t)=Emaxe−kCxcos(kCx−ωt) by substituting Ey(x,t) in ∂2Ey(x,t)∂x2=μρ ∂Ey(x,t)∂t

Answer 7

Chapter 32, Problem 56E

(a)

To determine

To verify: The solution to the wave equation is Ey(x,t)=Emaxe−kCxcos(kCx−ωt) by substituting Ey(x,t) in ∂2Ey(x,t)∂x2=μρ ∂Ey(x,t)∂t

Answer 8

(b)

To determine

To explain: Why the electric field decreases in amplitude as wave propagates.

Answer 9

(b)

To determine

To explain: Why the electric field decreases in amplitude as wave propagates.

Answer 10

(c)

To determine

To show: The electric field amplitude decreases by a factor of 1e in a distance 1kC=2ρωμ and to calculate that distance for a radio wave with frequency f=1.0 MHz in copper.

Answer 11

(c)

To determine

To show: The electric field amplitude decreases by a factor of 1e in a distance 1kC=2ρωμ and to calculate that distance for a radio wave with frequency f=1.0 MHz in copper.

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

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Answer 15

Ch. 32 - Prob. 1DQ Ch. 32 - Prob. 2DQ Ch. 32 - Prob. 3DQ Ch. 32 - Prob. 4DQ Ch. 32 - Prob. 5DQ Ch. 32 - Prob. 6DQ Ch. 32 - Prob. 7DQ Ch. 32 - Prob. 8DQ Ch. 32 - Prob. 9DQ Ch. 32 - Prob. 10DQ

To verify: The solution to the wave equation is E y ( x , t ) = E max e − k C x cos ( k C x − ω t ) by substituting E y ( x , t ) in ∂ 2 E y ( x , t ) ∂ x 2 = μ ρ ∂ E y ( x , t ) ∂ t

To verify: The solution to the wave equation is Ey(x,t)=Emaxe−kCxcos(kCx−ωt) by substituting Ey(x,t) in ∂2Ey(x,t)∂x2=μρ ∂Ey(x,t)∂t

To explain: Why the electric field decreases in amplitude as wave propagates.

To show: The electric field amplitude decreases by a factor of 1e in a distance 1kC=2ρωμ and to calculate that distance for a radio wave with frequency f=1.0 MHz in copper.

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Chapter 32 Solutions