Explanation Given information: The polynomial is P ( x ) = − 1 2 x 3 + 3 2 x − 1 . Calculation: Redraw the graph of the polynomial P ( x ) = − 1 2 x 3 + 3 2 x − 1 as shown in Figure 1, To determine (b) To find: The coordinate of the all local extrema of the polynomial P ( x ) = − 1 2 x 3 + 3 2 x − 1 .

7th Edition

ISBN: 9781305115545

Author: James Stewart, Lothar Redlin, Saleem Watson

Publisher: Cengage Learning

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Chapter 3.2, Problem 53E

To determine

(a)

To find:

The value of x and y intercept of the polynomial P(x)=−12x3+32x−1 from the given graph.

To determine

(b)

To find:

The coordinate of the all local extrema of the polynomial P(x)=−12x3+32x−1.

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Chapter 3.2, Problem 52E

Chapter 3.2, Problem 54E

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(a) To find: The value of x and y intercept of the polynomial P ( x ) = − 1 2 x 3 + 3 2 x − 1 from the given graph.

Solution Summary: The author calculates the value of x and -y intercepts of the polynomial P(x) from the given graph.

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(a)

To find:

The value of x and y intercept of the polynomial P(x)=−12x3+32x−1 from the given graph.

(b)

To find:

The coordinate of the all local extrema of the polynomial P(x)=−12x3+32x−1.

Want to see the full answer?

Chapter 3 Solutions

(a) To find: The value of x and y intercept of the polynomial P ( x ) = − 1 2 x 3 + 3 2 x − 1 from the given graph.

Solution Summary: The author calculates the value of x and -y intercepts of the polynomial P(x) from the given graph.

Concept explainers

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(a) To find: The value of x and y intercept of the polynomial P(x)=−12x3+32x−1 from the given graph.

(b) To find: The coordinate of the all local extrema of the polynomial P(x)=−12x3+32x−1.

Want to see the full answer?

Chapter 3 Solutions

(a)

To find:

The value of x and y intercept of the polynomial P(x)=−12x3+32x−1 from the given graph.

(b)

To find:

The coordinate of the all local extrema of the polynomial P(x)=−12x3+32x−1.