a) Magnetization M = N μ · t a n h μ B k T b) Magnetization M for μ B ≪ k T is M = N μ 2 B k B T c) Magnetization M for μ B ≫ k T is M = N μ d) Both (b) and (c) agree qualitatively with figure 32-14.

Question

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Answer 1

Question

Chapter 32, Problem 45P

To determine

To show:

a) Magnetization M=Nμ·tanhμBkT

b) Magnetization M for μB≪kT is M=Nμ2BkBT

c) Magnetization M for μB≫kT is M=Nμ

d) Both (b) and (c) agree qualitatively with figure 32-14.

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Answer 2

Question

Chapter 32, Problem 45P

To determine

To show:

a) Magnetization M=Nμ·tanhμBkT

b) Magnetization M for μB≪kT is M=Nμ2BkBT

c) Magnetization M for μB≫kT is M=Nμ

d) Both (b) and (c) agree qualitatively with figure 32-14.

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Answer 3

Question

Chapter 32, Problem 45P

To determine

To show:

a) Magnetization M=Nμ·tanhμBkT

b) Magnetization M for μB≪kT is M=Nμ2BkBT

c) Magnetization M for μB≫kT is M=Nμ

d) Both (b) and (c) agree qualitatively with figure 32-14.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 32, Problem 45P

To determine

To show:

a) Magnetization M=Nμ·tanhμBkT

b) Magnetization M for μB≪kT is M=Nμ2BkBT

c) Magnetization M for μB≫kT is M=Nμ

d) Both (b) and (c) agree qualitatively with figure 32-14.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 32, Problem 45P

To determine

To show:

a) Magnetization M=Nμ·tanhμBkT

b) Magnetization M for μB≪kT is M=Nμ2BkBT

c) Magnetization M for μB≫kT is M=Nμ

d) Both (b) and (c) agree qualitatively with figure 32-14.

Answer 6

Chapter 32, Problem 45P

To determine

To show:

a) Magnetization M=Nμ·tanhμBkT

b) Magnetization M for μB≪kT is M=Nμ2BkBT

c) Magnetization M for μB≫kT is M=Nμ

d) Both (b) and (c) agree qualitatively with figure 32-14.

Answer 7

Chapter 32, Problem 45P

To determine

To show:

a) Magnetization M=Nμ·tanhμBkT

b) Magnetization M for μB≪kT is M=Nμ2BkBT

c) Magnetization M for μB≫kT is M=Nμ

d) Both (b) and (c) agree qualitatively with figure 32-14.

Answer 8

Expert Solution & Answer

Answer 9

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Answer 10

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Answer 11

Ch. 32 - Figure 32-19a shows a capacitor, with circular...Ch. 32 - Prob. 2Q Ch. 32 - Prob. 3Q Ch. 32 - Figure 32-22a shows a pair of opposite spin...Ch. 32 - An electron in an external magnetic field Bext has...Ch. 32 - Prob. 6Q Ch. 32 - Figure 32-23 shows a face-on view of one of the...Ch. 32 - Prob. 8Q Ch. 32 - Replace the current loops of Question 8 and Fig....Ch. 32 - Prob. 10Q

a) Magnetization M = N μ · t a n h μ B k T b) Magnetization M for μ B ≪ k T is M = N μ 2 B k B T c) Magnetization M for μ B ≫ k T is M = N μ d) Both (b) and (c) agree qualitatively with figure 32-14.

Solution Summary: The author explains that the plotted graph has a similar nature, so (b) and (c) agree qualitatively with figure 32-14.

Concept explainers

To show:

a) Magnetization M=Nμ·tanhμBkT

b) Magnetization M for μB≪kT is M=Nμ2BkBT

c) Magnetization M for μB≫kT is M=Nμ

d) Both (b) and (c) agree qualitatively with figure 32-14.

Want to see the full answer?

Chapter 32 Solutions

a) Magnetization M = N μ · t a n h μ B k T b) Magnetization M for μ B ≪ k T is M = N μ 2 B k B T c) Magnetization M for μ B ≫ k T is M = N μ d) Both (b) and (c) agree qualitatively with figure 32-14.

Solution Summary: The author explains that the plotted graph has a similar nature, so (b) and (c) agree qualitatively with figure 32-14.

Concept explainers

To show: a) Magnetization M=Nμ·tanhμBkT b) Magnetization M for μB≪kT is M=Nμ2BkBT c) Magnetization M for μB≫kT is M=Nμ d) Both (b) and (c) agree qualitatively with figure 32-14.

Want to see the full answer?

Chapter 32 Solutions

To show:

a) Magnetization M=Nμ·tanhμBkT

b) Magnetization M for μB≪kT is M=Nμ2BkBT

c) Magnetization M for μB≫kT is M=Nμ

d) Both (b) and (c) agree qualitatively with figure 32-14.