Pre-Algebra
Pre-Algebra
1st Edition
ISBN: 9780618800766
Author: Ron Larson, Lee Stiff, Laurie Boswell, Timothy Kanold
Publisher: Houghton Mifflin-High School
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Chapter 3.2, Problem 37E

a.

To determine

To write the equation for the totalphone bill of last month with m extra minutes.

a.

Expert Solution
Check Mark

Answer to Problem 37E

Theequationfor the totalphone bill of last month with m extra minutes.

  29.50=19.50+0.25⋅m

Explanation of Solution

Given information :

Consider, the equationfor the totalphone bill of last month with m extra minutes.

  29.50=19.50+0.25⋅m

Calculation :

To derive the equation, for the totalphone bill of last month with m extra minutes,

  29.50=19.50+0.25⋅m

Therefore,

The equationfor the totalphone bill of last month with m extra minutes.

  29.50=19.50+0.25⋅m

b.

To determine

To solve the equation.

b.

Expert Solution
Check Mark

Answer to Problem 37E

The solution of the equation, for the totalphone bill of last month with m extra minutes

  m=40

Explanation of Solution

Given information :

Consider, the equationfor the totalphone bill of last month with m extra minutes

  29.50=19.50+0.25⋅m

Calculation :

The solution of the equation, for the totalphone bill of last month with m extra minutes.

  29.50=19.50+0.25⋅m               29.50−19.50=19.50−19.50+0.25⋅m                       [subtract 19.50 from each side]10=0.25m10÷0.25=0.25m÷0.25                                               [divide each side by 0.25]m=40

Therefore,

The solution of the equation, for the totalphone bill of last month with m extra minutes

  m=40

c.

To determine

To calculate : the additional minutes used last month,

c.

Expert Solution
Check Mark

Answer to Problem 37E

The additional minutes used last month,

  m=40  minutes

Explanation of Solution

Given information :

Consider, the equation forthe additional minutes used last month,

  29.50=19.50+0.25⋅m               

Calculation :

The value of the equation, for the additional minutes used last month,

  29.50=19.50+0.25⋅m               29.50−19.50=19.50−19.50+0.25⋅m                       [subtract 19.50 from each side]10=0.25m10÷0.25=0.25m÷0.25                                               [divide each side by 0.25]m=40

Since,

The additional minutes used last month is m minutes,

Hence,

The value of the equation, for the additional minutes used last month,

  m=40  minutes

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Chapter 3.2, Problem 36E
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Chapter 3.2, Problem 38E

Chapter 3 Solutions

Pre-Algebra

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