Architectural Drafting and Design (MindTap Course List)
7th Edition
ISBN: 9781285165738
Author: Alan Jefferis, David A. Madsen, David P. Madsen
Publisher: Cengage Learning
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Textbook Question
Chapter 32, Problem 32.1Q
What are the two major methods of determining lateral loads?
Expert Solution & Answer
To determine
The two major methods of determining lateral loads.
Answer to Problem 32.1Q
Extra blocking and metal connectors to tie posts of one level to members below them are methods of determining lateral loads.
Explanation of Solution
Lateral loads on a structure cause a side-movement. Seismic activity and wind cause lateral loads. Based on the country area where the building is situated, the magnitude of lateral loads can vary greatly.
OSB shear panels or plywood, metal connectors to tie posts of one level to members below them, metal angles and extra blocking are common methods of resisting lateral loads.
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8. A prestressed concrete beam is subjected to the
following stress distributions:
Pi is the initial prestressing force, Pe is the effective
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moment, respectively.
The concrete has the following properties: fr = 6000 psi
and fri = 4200 psi
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P alone
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-2450 -3500
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+210
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Using Table 22.1, evaluate whether the stresses at the center of the span and the end of the span comply with the
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10. A short column is subjected to an eccentric loading. The axial load P =
1000 kips and the eccentricity e = 12 in. The material strengths are fy = 60 ksi
and f = 6000 psi. The Young's modulus of steel is 29000 ksi.
(a) Fill in the blanks in the interaction diagram shown below.
(2pts each, 10pt total)
Po
Pn
(1)
failure range
H
3"
30"
Ast 6 No. 10 bars
=
P
22"
I
e
H
3"
(4) e =
e small
Load
path for
given e
Radial lines show constant (2)
eb
(3)
e large
failure range
Mn
(5) e=
Mo
(b) Compute the balanced failure point, i.e., P and Mb.
Chapter 32 Solutions
Architectural Drafting and Design (MindTap Course List)
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- No chatgpt plsarrow_forward11. The prestressed T beam shown below is pretensioned using low relaxation stress-relieved Grade 270 strands. The steel area Aps = 2.5 in². The tensile strength is fpu = 270 ksi, and the concrete compressive strength is fr = 6000 psi. (a) Calculate the nominal moment strength Mn with hr = 6 in. 22" 15" T hf (b) Since this beam is a T-beam, the nominal moment strength M₁ increases with a thicker hf. However, M, stops increasing if he reaches a value. Determine the minimum thickness hy that can achieve the maximum nominal moment strength Mr. Also, calculate the corresponding maximum nominal moment strength Mn with the computed hf.arrow_forward10. A short column is subjected to an eccentric loading. The axial load P = 1000 kips and the eccentricity e = 12 in. The material strengths are fy = 60 ksi and f = 6000 psi. The Young's modulus of steel is 29000 ksi. (a) Fill in the blanks in the interaction diagram shown below. 30" Ast 6 No. 10 bars = Pn (1) Po (4) e = e small Load path for given e failure range Radial lines show constant (2) eb (3) e large failure range Mn (5) e= Mo (b) Compute the balanced failure point, i.e., P and Mb. H 3" P 22" I e H 3"arrow_forward
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