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For Exercises 23–38, find the zeros of the function and state the multiplicities. (See Examples 2–4)
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COLLEGE ALGEBRA CUSTOM TEXT WITH ALEKS 3
- Determine which functions have two real number zeros by calculating the discriminant, b2 – 4ac. Check all that apply. O fx) = x² + 6x + 8 O g(x) = x² + 4x + 8 O h(x) = x2 – 12x + 32 O k(x) = x2 + 4x – 1 O p(x) = 5x2 + 5x + 4 O t(x) = x2 – 2x – 15 -arrow_forwardRead and understand the lessons on transforming and graphing quadratic functions on pages 26– 30 in PIVOT 4A Grade - 9 Mathematics Answer the following: I. Transform the quadratic function defined by y = ax2 + bx+ c into the form y = a(x-h)² + k. -1 --i-1 1. y = x2 – 6x – 3 2. y = 5x2 – 20x – 5arrow_forwardIn Exercises 27–28, let f and g be defined by the following table: f(x) g(x) -2 -1 3 4 -1 1 1 -4 -3 -6 27. Find Vf(-1) – f(0) – [g(2)]² + f(-2) ÷ g(2) ·g(-1). 28. Find |f(1) – f0)| – [g(1)] + g(1) ÷ f(-1)· g(2).arrow_forward
- The Mauna Loa Observatory in Hawaii records the carbon dioxide concentration y (in parts per million) in Earth’s atmosphere. The January readings for various years are shown in Figure . In the July 1990 issue of Scientific American, these data were used to predict the carbon dioxide level in Earth’s atmosphere in the year 2035, using the quadratic model y = 0.018t2 + 0.70t + 316.2 (Quadratic model for 1960–1990 data) where t = 0 represents 1960, as shown in Figure a. The data shown in figure b represent the years 1980 through 2014 and can be modeled by y = 0.014t2 + 0.66t + 320.3 (Quadratic model for 1980–2014) data where t = 0 represents 1960. What was the prediction given in the Scientific American article in 1990? Given the second model for 1980 through 2014, does this prediction for the year 2035 seem accurate?arrow_forwardIn Exercises 33–38, express the function, f, in simplified form. Assume that x can be any real number. 33. f(x) = V36(x + 2)² 34. f(x) = V81(x – 2)2 35. f(x) = V32(x + 2)³ 36. f(x) = V48(x – 2)³ 37. f(x) = V3x² – 6x + 3 38. f(x) = V5x2 – 10x + 5 %3Darrow_forwardIn Problems 81–98, analyze each polynomial functionarrow_forward
- For Exercises 75–84, determine the r- and y-intercepts for the given function. (See Example 7) 75. f(x) = 2x – 4 76. g(x) = 3x – 12 77. h(x) = |x| – 8 78. k(x) = -|x| + 2 79. p(x) = -x + 12 80. q(x) = - 8 81. r(x) = |x – 8| 82. s(x) = |x + 3| 83. f(x) = Vx – 2 84. g(x) = – Vx + 3arrow_forwardIn Problems 99–106, analyze each polynomial function farrow_forwardPart A: f(a+h) Part B: f(a) Part C: f(a+h)-f(a) Part D: f(a+h)-f(a) all divided by harrow_forward
- Find the difference quotient and simplify your answer. f(6 + h) – f(6) Ax) = x2 – x+ 1, -, h+0 h f(6 + h) – f(6) = h + 12, h+ 0 h f(6 + h) – f(6) = h + 13, h+0 %3D h f(6 + h) – f(6) = h + 14, h± 0 h f(6 + h) – f(6) = h + 15, h+ 0 %3D h f(6 + h) – f(6) h + 11, h+ 0 harrow_forwardExercises 125-130: Evaluate the expression for the given function f. 125. f(a + 2) for f(x) = 3 – 4x² 126. f(a – 3) for S(x) = x² + 2x 127. f(a + h) for f(x) = x² – x + 5 128. f(a – h) for {(x) = 1 – 4x – x² 129. f(a + h) – f(a) for f(x) = 2x² + 3 130. f(a + h) – f(a) for f(x) = x – x²arrow_forwardWhich function is equivalent tof (x) = -4(x+ 7)² – 6? %3D F.f (x) = -4x2 - 56x – 202 %3D G.f(x) = -4x2 + 14x + 43 %3D H.f(x) = -4x² - 56x – 172 %3D J.f(x)= -4x2 + 190 OF H.arrow_forward
- Trigonometry (MindTap Course List)TrigonometryISBN:9781337278461Author:Ron LarsonPublisher:Cengage LearningBig Ideas Math A Bridge To Success Algebra 1: Stu...AlgebraISBN:9781680331141Author:HOUGHTON MIFFLIN HARCOURTPublisher:Houghton Mifflin Harcourt