To determine The Wronskian of the pair of functions e 2 t , e − 3 t 2 . Explanation Formula used: The Wronskian determinant of two functions y 1 and y 2 is given by W = y 1 y ′ 2 − y ′ 1 y 2 . Calculation: The given pair of functions are e 2 t , e − 3 t 2 . Ley y 1 = e 2 t , y 2 = e − 3 t 2 Differentiate y 1 = e 2 t with respect to t and obtain the value of y ′ 1 as shown below: y 1 = e 2 t y ′ 1 = 2 e 2 t Thus, y ′ 1 = 2 e 2 t . Differentiate y 2 = e − 3 t 2 with respect to t and obtain the value of y ′ 2 as shown below: y 2 = e − 3 t 2 y ′ 2 = − 3 2 e − 3 t 2 Thus, y ′ 2 = − 3 2 e − 3 t 2

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ISBN: 9780470458327

Author: William E. Boyce, Richard C. DiPrima

Publisher: Wiley, John & Sons, Incorporated

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Chapter 3.2, Problem 1P

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The Wronskian of the pair of functions e2t,e−3t2.

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Chapter 3.1, Problem 28P

Chapter 3.2, Problem 2P

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Elementary Differential Equations

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