Bisection Method for Approximating Zeros of a Function f We begin with two consecutive integers, a and a + 1 , such that f ( a ) and f ( a + 1 ) are of opposite sign. Evaluate f at the midpoint m 1 of a and a + 1 . If f ( m 1 ) = 0 . then m 1 is the zero of f , and we are finished. Otherwise, f ( m 1 ) is of opposite sign to either f ( a ) or f ( a + 1 ) . Suppose that it is f ( a ) and f ( m 1 ) that are of opposite sign. Now evaluate f at the midpoint m 2 of a and m 1 . Repeat this process until the desired degree of accuracy is obtained. Note that each iteration places the zero in an interval whose length is half that of the previous interval. Use the bisection method to approximate the zero of f ( x ) = 8 x 4 − 2 x 2 + 5 x − 1 in the interval [ 0 , 1 ] correct to three decimal places. Verify your result using a graphing utility. [ Hint: The process ends when both endpoints agree to the desired number of decimal places.]
Bisection Method for Approximating Zeros of a Function f We begin with two consecutive integers, a and a + 1 , such that f ( a ) and f ( a + 1 ) are of opposite sign. Evaluate f at the midpoint m 1 of a and a + 1 . If f ( m 1 ) = 0 . then m 1 is the zero of f , and we are finished. Otherwise, f ( m 1 ) is of opposite sign to either f ( a ) or f ( a + 1 ) . Suppose that it is f ( a ) and f ( m 1 ) that are of opposite sign. Now evaluate f at the midpoint m 2 of a and m 1 . Repeat this process until the desired degree of accuracy is obtained. Note that each iteration places the zero in an interval whose length is half that of the previous interval. Use the bisection method to approximate the zero of f ( x ) = 8 x 4 − 2 x 2 + 5 x − 1 in the interval [ 0 , 1 ] correct to three decimal places. Verify your result using a graphing utility. [ Hint: The process ends when both endpoints agree to the desired number of decimal places.]
Solution Summary: The author explains the bisection method to approximate the zero of f ( x ) = 8 2 / 2 + 5 in the interval.
Bisection Method for Approximating Zeros of a Function
We begin with two consecutive integers,
and
, such that
and
are of opposite sign. Evaluate
at the midpoint
of
and
. If
. then
is the zero of
, and we are finished. Otherwise,
is of opposite sign to either
or
. Suppose that it is
and
that are of opposite sign. Now evaluate
at the midpoint
of
and
. Repeat this process until the desired degree of accuracy is obtained. Note that each iteration places the zero in an interval whose length is half that of the previous interval. Use the bisection method to approximate the zero of
in the interval
correct to three decimal places. Verify your result using a graphing utility.
[Hint: The process ends when both endpoints agree to the desired number of decimal places.]
8–23. Sketching vector fields Sketch the following vector fields
25-30. Normal and tangential components For the vector field F and
curve C, complete the following:
a. Determine the points (if any) along the curve C at which the vector
field F is tangent to C.
b. Determine the points (if any) along the curve C at which the vector
field F is normal to C.
c. Sketch C and a few representative vectors of F on C.
25. F
=
(2½³, 0); c = {(x, y); y −
x² =
1}
26. F
=
x
(23 - 212) ; C = {(x, y); y = x² = 1})
,
2
27. F(x, y); C = {(x, y): x² + y² = 4}
28. F = (y, x); C = {(x, y): x² + y² = 1}
29. F = (x, y); C =
30. F = (y, x); C =
{(x, y): x = 1}
{(x, y): x² + y² = 1}
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