The difference between atomic structure and crystal structure.

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For the design of a shallow foundation, given the following: Soil: ' = 20° c=57 kN/m² Unit weight, y=18 kN/m³ Modulus of elasticity, E, = 1400 kN/m² Poisson's ratio, μs = 0.35 Foundation: L=2m B=1m D₁ =1m Calculate the ultimate bearing capacity. Use the equation: 1 qu= c'Ne Fes Fed Fec +qNqFqs FqdFqc + - BNF √s F√d F 2 For d'=20°, N = 14.83, N = 6.4, and N., = 5.39. (Enter your answer to three significant figures.) qu kN/m²

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Chapter 3.17, Problem 1QP

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The difference between atomic structure and crystal structure.

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For the design of a shallow foundation, given the following: Soil: ' = 20° c=57 kN/m² Unit weight, y=18 kN/m³ Modulus of elasticity, E, = 1400 kN/m² Poisson's ratio, μs = 0.35 Foundation: L=2m B=1m D₁ =1m Calculate the ultimate bearing capacity. Use the equation: 1 qu= c'Ne Fes Fed Fec +qNqFqs FqdFqc + - BNF √s F√d F 2 For d'=20°, N = 14.83, N = 6.4, and N., = 5.39. (Enter your answer to three significant figures.) qu kN/m²

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