To determine To solve: The differential equation d V d P = V P 2 . Explanation Definition used: A differential equation of the first order and first degree contains the first derivative to the first power. That is, it may be written as d y d x = f ( x , y ) . The differential form of the above equation is, M ( x , y ) d x + N ( x , y ) d y = 0 , where M ( x , y ) and N ( x , y ) may represent constants, functions of either x or y , or functions of x and y . Procedure used: To solve an equation of the form of M ( x , y ) d x + N ( x , y ) d y = 0 , find the solution by integrating each term and adding the constant of integration . Calculation: The given differential equation is d V d P = V P 2 . Separate the terms with variables V and P as, d V V = – d P P 2 . Integrate on both the sides of the above equation as, ∫ d V V = – ∫ d P P 2 ∫ d V V =

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ISBN: 9780134437705

Author: Washington

Publisher: PEARSON

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Chapter 31.2, Problem 17E

To determine

To solve: The differential equation dVdP = VP2.

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Chapter 31.2, Problem 16E

Chapter 31.2, Problem 18E

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Chapter 31 Solutions

Basic Technical Mathematics

Ch. 31.1 - Show that is a solution of . Is it the general...Ch. 31.1 - Prob. 1E Ch. 31.1 - In Exercises 1 and 2, show that the indicated...Ch. 31.1 - In Exercises 3–6, determine whether the given...Ch. 31.1 - Prob. 4E Ch. 31.1 - In Exercises 3–6, determine whether the given...Ch. 31.1 - Prob. 6E Ch. 31.1 - In Exercises 7–10, show that each function y =...Ch. 31.1 - Prob. 8E Ch. 31.1 - In Exercises 7–10, show that each function y =...

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