(a) Explanation Given info: The de-Broglie wavelength of an electron is 3.99 × 10 − 9 m . According to Bohr’s theory, the circumference of orbit is, 2 π r n = n λ n Here, r n is the radius of n th orbit. λ is the de-Broglie wavelength of n th orbit. n is the n th state of an electron. The radius of n th orbit is, r n = n 2 r 1 Here, r 1 is the radius of Bohr’s first orbit. The radius of Bohr’s first orbit is 5.29 × 10 − 11 m . Substitute n 2 r 1 for r n to calculate n λ n (b) To determine The Bohr radius of the state.

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Author: James S. Walker

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Chapter 31, Problem 89PP

(a)

To determine

The state that has de-Broglie wavelength of 3.99×10−9 m .

(b)

To determine

The Bohr radius of the state.

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Chapter 31, Problem 88PP

Chapter 32.1, Problem 1EYU

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The state that has de-Broglie wavelength of 3.99 × 10 − 9 m .

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The state that has de-Broglie wavelength of 3.99×10−9 m .

The Bohr radius of the state.

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Chapter 31 Solutions