Honeycomb The surface area of a cell in a honeycomb is S = 6 h s + 3 s 2 2 ( 3 − cos θ sin θ ) where h and s are positive constants and θ is the angle at which the upper faces meet the altitude of the cell (see figure). Find the angle θ ( π / 6 ≤ θ ≤ π / 2 ) that minimizes the surface area S .
Honeycomb The surface area of a cell in a honeycomb is S = 6 h s + 3 s 2 2 ( 3 − cos θ sin θ ) where h and s are positive constants and θ is the angle at which the upper faces meet the altitude of the cell (see figure). Find the angle θ ( π / 6 ≤ θ ≤ π / 2 ) that minimizes the surface area S .
Honeycomb The surface area of a cell in a honeycomb is
S
=
6
h
s
+
3
s
2
2
(
3
−
cos
θ
sin
θ
)
where h and s are positive constants and
θ
is the angle at which the upper faces meet the altitude of the cell (see figure). Find the angle
θ
(
π
/
6
≤
θ
≤
π
/
2
)
that minimizes the surface area S.
a
->
f(x) = f(x) = [x] show that whether f is continuous function or not(by using theorem)
Muslim_maths
Use Green's Theorem to evaluate F. dr, where
F = (√+4y, 2x + √√)
and C consists of the arc of the curve y = 4x - x² from (0,0) to (4,0) and the line segment from (4,0) to
(0,0).
Evaluate
F. dr where F(x, y, z) = (2yz cos(xyz), 2xzcos(xyz), 2xy cos(xyz)) and C is the line
π 1
1
segment starting at the point (8,
'
and ending at the point (3,
2
3'6
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