Explanation Given information: f ( x ) = 2 x 3 − 5 x 2 + 3 x − 5 at x = 1. Formula used: The slope-intercept form of the equation is y − y 1 = m ( x − x 1 ) The slope m of the tangent line is m = f ' ( x 0 ) where x 0 is the x-coordinate of the given point. Calculation: f ( x ) = 2 x 3 − 5 x 2 + 3 x − 5 (Given) Differentiating with respect to ‘x’, we get f ' ( x ) = 2 ( 3 x 2 ) − 5 ( 2 x ) + 3 ( 1 ) − 0 = 6 x 2 − 10 x + 3 Substituting the x coordinate of the given point, that is x = 1 in the above equation, we get f ' ( 1 ) = 6 ( 1 ) 2 − 10 ( 1 ) + 3 = 6 − 10 + 3 ⇒ m = − 1 Substituting m = − 1 in the equation y − y 1 = m ( x − x 1 ) , we get y − y 1 = − 1 ( x − x<

6th Edition

ISBN: 9781119267874

Author: Hughes-Hallett

Publisher: WILEY

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Chapter 3.1, Problem 58P

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The equation for the tangent line to the graph of f(x)=2x3−5x2+3x−5 at x=1.

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Chapter 3.1, Problem 57P

Chapter 3.1, Problem 59P

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The equation for the tangent line to the graph of f ( x ) = 2 x 3 − 5 x 2 + 3 x − 5 at x = 1.

Solution Summary: The author explains the equation for the tangent line to the graph of f(x)=2x3-5 x 2+3x-5. The slope-intercept form of

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The equation for the tangent line to the graph of f(x)=2x3−5x2+3x−5 at x=1.

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Chapter 3 Solutions

The equation for the tangent line to the graph of f ( x ) = 2 x 3 − 5 x 2 + 3 x − 5 at x = 1.

Solution Summary: The author explains the equation for the tangent line to the graph of f(x)=2x3-5 x 2+3x-5. The slope-intercept form of

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To find: The equation for the tangent line to the graph of f(x)=2x3−5x2+3x−5 at x=1.

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Chapter 3 Solutions

To find:

The equation for the tangent line to the graph of f(x)=2x3−5x2+3x−5 at x=1.