Explanation Given: A 6 14 C source of 2.50 μ C i Formula used: • 1 C i = 3.7 × 10 10 ( − ln 1 2 ) N A m o l e s × t 1 2 (in seconds); where N A Avogadro’s No. • Atomic mass of C 6 14 is 14gm • t 1 2 for 6 14 C is 5730 years. Calculation: The number of moles corresponding to 2.50 μ C i 6 14 C source will be, n = 2...

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Publisher: PEARSON

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Chapter 31, Problem 47P

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The mass of $2.50 μ C_{i}$ $_{6}^{14} C$ source

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Chapter 31, Problem 46P

Chapter 31, Problem 48P

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4 Problem 4) A particle is being pushed up a smooth slot by a rod. At the instant when 0 = rad, the angular speed of the arm is ė = 1 rad/sec, and the angular acceleration is = 2 rad/sec². What is the net force acting on the 1 kg particle at this instant? Express your answer as a vector in cylindrical coordinates. Hint: You can express the radial coordinate as a function of the angle by observing a right triangle. (20 pts) Ꮎ 2 m Figure 3: Particle pushed by rod along vertical path.

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