Chapter 31, Problem 1FC

To determine

The correct option.

Answer to Problem 1FC

The correct option is $\underset{\_}{\left(e\right)\left({}_{49}^{115}\text{In}\right)}$.

Explanation of Solution

Given data:

Number of protons in indium nucleus is 49.

Number of neutrons in indium nucleus is 66.

Formula used:

Write the notation of nucleus with the representation of protons and neutrons.

$\text{X}$

Here,

Z represents the number of protons.

A represents the number of protons and neutrons.

Explanation:

For the value of A,

Number of protons is 49.

Number of neutrons is 66.

$\begin{array}{c}\text{Value of A}=\text{Number of protons}+\text{Number of neutrons}\\ =49+66\\ =115\end{array}$

For the value of Z,

Number of protons is 49.

$\begin{array}{c}\text{Value of Z}=\text{Number of protons}\\ =49\end{array}$

The option which represents the correct values of the protons and the neutrons with the symbol of Indium is (e).

Conclusion:

Hence, the correct option is $\underset{\_}{\left(e\right)\left({}_{49}^{115}\text{In}\right)}$.