Explanation Maclaurin series expansion: f ( x ) = f ( 0 ) + f ′ ( 0 ) x + f ″ ( 0 ) x 2 2 ! + f ‴ ( 0 ) x 3 3 ! + … + f n ( 0 ) x n n ! + … . Calculation: The given function is, f ( x ) = sec x . Differentiate the above function with respect to x . f ′ ( x ) = d d x ( sec x ) = sec x tan x Again, differentiate the function f ′ ( x ) with respect to x . f ″ ( x ) = d d x ( sec x tan x ) = sec x ( sec 2 x ) + tan x ( sec x tan x ) = sec 3 x + sec x tan 2 x Substitute x = 0 in the function f ( x ) , f ′ ( x ) and f ″ ( x )

11th Edition

ISBN: 9780134437705

Author: Washington

Publisher: PEARSON

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Chapter 30.2, Problem 24E

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The first two nonzero terms of the Maclaurin series expansion for the given function.

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Chapter 30.2, Problem 23E

Chapter 30.2, Problem 25E

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Chapter 30 Solutions

Basic Technical Mathematics

Ch. 30.1 - Prob. 1PE Ch. 30.1 - Prob. 2PE Ch. 30.1 - Prob. 1E Ch. 30.1 - Prob. 2E Ch. 30.1 - Prob. 3E Ch. 30.1 - Prob. 4E Ch. 30.1 - Prob. 5E Ch. 30.1 - Prob. 6E Ch. 30.1 - Prob. 7E Ch. 30.1 - Prob. 8E

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