Explanation Formula used: The number of nuclei remaining after a time t, N = N 0 e − λ t , N 0 is the number of nuclei present after time t = 0 and λ is the decay constant. Decay constant, λ = ln 2 T 1 / 2 , T 1 / 2 is the half life Activity = λ N , where λ is the decay constant and N is the number of nuclei remaining after a time t Calculation: We have initial decay rate = λ N 0 = 2.4 × 10 5 s − 1 We have Decay constant, λ = ln 2 1...

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Chapter 30, Problem 48P

To determine

The activity of a pure $6.7 μ g$ sample of ${}_{15}^{32}P$ ( $T_{1 / 2} = 1.23 \times 10^{6} s$ )?

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Chapter 30, Problem 47P

Chapter 30, Problem 49P

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Chapter 30 Solutions

PHYSICS:PRINCIPLES W/ APPLICATIONS

Ch. 30 - Prob. 1OQ Ch. 30 - Prob. 1Q Ch. 30 - Prob. 2Q Ch. 30 - Prob. 3Q Ch. 30 - Prob. 4Q Ch. 30 - Prob. 5Q Ch. 30 - Prob. 6Q Ch. 30 - Prob. 7Q Ch. 30 - Prob. 8Q Ch. 30 - Prob. 9Q

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