
Concept explainers
(a)
The magnitude and direction of magnetic field at point A
.
(a)

Answer to Problem 30.15P
Explanation of Solution
Given Info: The current flowing through the conductor is
Explanation:
Diagram of three parallel conductor having current of magnitude
Figure (1)
Formula to calculate side of the square is,
Formula to calculate angle
Formula to calculate magnetic field at point
Here
Substitute
Formula to calculate magnetic field at point
Here
Substitute
Formula to calculate magnetic field at point
Here
Substitute
Write the expression to calculate magnetic field at point
Here,
Substitute
substitute
Write the expression to calculate y-component of magnetic field at
Substitute
Formula to calculate net magnetic field at point
Substitute
Hence, magnetic field at point
Conclusion:
Therefore magnetic field at point
(b)
magnitude and direction of magnetic field at point B
.
(b)

Answer to Problem 30.15P
Explanation of Solution
Formula to calculate magnetic field at point
Here
Substitute
Formula to calculate magnetic field at point
Here
Substitute
Formula to calculate magnetic field at point
Here
Substitute
Write the expression to calculate magnetic field at point
Here,
Substitute
substitute
Write the expression to calculate y-component of magnetic field at
Substitute
Formula to calculate net magnetic field at point
Substitute
Hence, magnetic field at point
Conclusion:
Therefore magnetic field at point
(c)
magnitude and direction of magnetic field at point C
.
(c)

Answer to Problem 30.15P
Explanation of Solution
Formula to calculate magnetic field at point
Here
Substitute
Formula to calculate magnetic field at point
Here
Substitute
Formula to calculate magnetic field at point
Here
Substitute
Write the expression to calculate magnetic field at point
Here,
Substitute
Write the expression to calculate y-component of magnetic field at
Substitute
Formula to calculate net magnetic field at point
Substitute
Hence, magnetic field at point
Conclusion:
Therefore magnetic field at point
Want to see more full solutions like this?
Chapter 30 Solutions
PHYSICS 1250 PACKAGE >CI<
- 20. Two small conducting spheres are placed on top of insulating pads. The 3.7 × 10-10 C sphere is fixed whie the 3.0 × 107 C sphere, initially at rest, is free to move. The mass of each sphere is 0.09 kg. If the spheres are initially 0.10 m apart, how fast will the sphere be moving when they are 1.5 m apart?arrow_forwardpls help on allarrow_forwardpls help on thesearrow_forward
- pls help on all asked questions kindlyarrow_forwardpls help on all asked questions kindlyarrow_forward19. Mount Everest, Earth's highest mountain above sea level, has a peak of 8849 m above sea level. Assume that sea level defines the height of Earth's surface. (re = 6.38 × 106 m, ME = 5.98 × 1024 kg, G = 6.67 × 10 -11 Nm²/kg²) a. Calculate the strength of Earth's gravitational field at a point at the peak of Mount Everest. b. What is the ratio of the strength of Earth's gravitational field at a point 644416m below the surface of the Earth to a point at the top of Mount Everest? C. A tourist watching the sunrise on top of Mount Everest observes a satellite orbiting Earth at an altitude 3580 km above his position. Determine the speed of the satellite.arrow_forward
- pls help on allarrow_forwardpls help on allarrow_forward6. As the distance between two charges decreases, the magnitude of the electric potential energy of the two-charge system: a) Always increases b) Always decreases c) Increases if the charges have the same sign, decreases if they have the opposite signs d) Increases if the charges have the opposite sign, decreases if they have the same sign 7. To analyze the motion of an elastic collision between two charged particles we use conservation of & a) Energy, Velocity b) Momentum, Force c) Mass, Momentum d) Energy, Momentum e) Kinetic Energy, Potential Energyarrow_forward
- Physics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning





