a.
Check whether there is a guaranteed amount of water the farmers, ranchers, and cities will get from the Yellowstone River each year.
a.

Answer to Problem 9CRP
No, there is no guaranteed amount of water the farmers, ranchers, and cities get from the Yellowstone River each year.
Explanation of Solution
The important source of water for wildlife, rancher, farmers, and cities downstream is Yellowstone River. The data show that the annual flow for recent 19 years of the Yellowstone River, which does not show any guarantee that they give water for each year.
The annual flows are random variables. Hence, there is no guaranteed amount of water the farmers, ranchers, and cities will get from the Yellowstone River each year.
b.
Find the expected annual flow from the Yellowstone snowmelt.
Find the
b.

Answer to Problem 9CRP
The expected annual flow from the Yellowstone snowmelt is 27.05.
The value of mean is 27.05.
The value of median is 25.9.
The value of mode is 25.9.
Explanation of Solution
Step-by-step procedure to obtain the mean, median, and mode using the MINITAB software:
- Choose Stat > Basic Statistics > Display
Descriptive Statistics . - In Variables enter the columns Annual flow.
- Check Options, Select Mean, Median and Mode.
- Click OK in all dialogue boxes.
The output obtained using the MINITAB software is given below:
From the MINITAB output, the value of mean is 27.05, the value of median is 25.9, and the value of mode is 25.9.
c.
Find the
c.

Answer to Problem 9CRP
The range is 27.6.
The value of standard deviation is 6.61.
Explanation of Solution
Step-by-step procedure to obtain the range and standard deviation using the MINITAB software:
- Choose Stat > Basic Statistics > Display Descriptive Statistics.
- In Variables enter the columns Annual flow.
- Check Options, Select Mean, Median and Mode.
- Click OK in all dialogue boxes.
The output obtained using the MINITAB software is given below:
From the MINITAB output, the range is 27.6 and the value of standard deviation is 6.61.
d.
Find the 75% Chebyshev interval around the mean.
d.

Answer to Problem 9CRP
The 75% Chebyshev interval around the mean is 13.83 and 40.27.
Explanation of Solution
The 75% Chebyshev interval around the mean is obtained below:
Thus, the 75% Chebyshev interval around the mean for Grid E is 0.77 and 39.93.
e.
Find the five-number summary of the annual water flow.
Draw the box-and-whisker plot.
Interpret the five-number summary and box-and-whisker plot.
Find the values where the middle portion of the data lies.
Find the
Identify the data outliers.
e.

Answer to Problem 9CRP
The five-number summary of the annual water flow is 17.5, 23.7, 25.9, 31.8, and 45.1.
The box-and-whisker plot is shown below:
The middle portion of the data lies between 23.7 and 31.8.
The value of interquartile range is 8.1.
The value 45.1 is an outlier.
Explanation of Solution
Step-by-step procedure to obtain the five-number summary of the annual water flow using MINITAB software:
- Choose Stat > Basic Statistics > Display Descriptive Statistics.
- In Variables enter the columns Annual flow.
- Check Options, Select Minimum, Maximum, first
quartile , Median, third quartile and IQR. - Click OK in all dialogue boxes.
The output obtained using the MINITAB software is given below:
From the MINITAB output, the five-number summary of annual water flow is 17.5, 23.7, 25.9, 31.8, and 45.1.
Step-by-step procedure to draw the box-and-whisker plot using the MINITAB software:
- Choose Graph > Boxplot or Stat > EDA > Boxplot.
- Under One Y, choose Simple. Click OK.
- In Graph variables, enter the data of Annual flow.
- Click OK in all dialogue boxes.
Interpretation:
From the box-and-whisker plot, it is observed that the distribution of the annual water flow is skewed to the right.
From the output, it is observed that the middle portion of the data lies between 23.7 and 31.8.
From the MINITAB output, the value of interquartile range is 8.1.
From the box-and-whisker plot, it is observed that the value 45.1 is an outlier.
f.
Check whether the Madison is more reliable using the coefficient of variation.
f.

Explanation of Solution
Step-by-step procedure to obtain the coefficient of variation using the MINITAB software:
- Choose Stat > Basic Statistics > Display Descriptive Statistics.
- In Variables enter the columns Yellowstone and Madison.
- Check Options, Select coefficient of variation.
- Click OK in all dialogue boxes.
The output obtained using the MINITAB software is given below:
From the MINITAB output, the coefficient of variation for the annual water flow of Yellowstone is 24.43, and the coefficient of variation for the annual water flow of Madison is 16.6.
From the result, it is observed that the coefficient of variation for the water flow of Madison is smaller when compared to the coefficient of variation for the annual water flow of Yellowstone. This indicates that the spread of river flow is smaller for Madison river. Hence, the Madison flower is more consistent.
g.
Check whether it is safe to allocate at least 27 units of Yellowstone River water each year for agricultural and domestic use.
g.

Explanation of Solution
From the results, it is observed that the median water flow of Yellowstone River is 25.9, which indicates that more than half of the river flows are below 27 units.
Hence, it is not safe to allocate at least 27 units of Yellowstone River water each year for agricultural and domestic use.
Want to see more full solutions like this?
Chapter 3 Solutions
Bundle: Understandable Statistics: Concepts And Methods, 12th + Webassign, Single-term Printed Access Card
- A normal distribution has a mean of 50 and a standard deviation of 4. Solve the following three parts? 1. Compute the probability of a value between 44.0 and 55.0. (The question requires finding probability value between 44 and 55. Solve it in 3 steps. In the first step, use the above formula and x = 44, calculate probability value. In the second step repeat the first step with the only difference that x=55. In the third step, subtract the answer of the first part from the answer of the second part.) 2. Compute the probability of a value greater than 55.0. Use the same formula, x=55 and subtract the answer from 1. 3. Compute the probability of a value between 52.0 and 55.0. (The question requires finding probability value between 52 and 55. Solve it in 3 steps. In the first step, use the above formula and x = 52, calculate probability value. In the second step repeat the first step with the only difference that x=55. In the third step, subtract the answer of the first part from the…arrow_forwardIf a uniform distribution is defined over the interval from 6 to 10, then answer the followings: What is the mean of this uniform distribution? Show that the probability of any value between 6 and 10 is equal to 1.0 Find the probability of a value more than 7. Find the probability of a value between 7 and 9. The closing price of Schnur Sporting Goods Inc. common stock is uniformly distributed between $20 and $30 per share. What is the probability that the stock price will be: More than $27? Less than or equal to $24? The April rainfall in Flagstaff, Arizona, follows a uniform distribution between 0.5 and 3.00 inches. What is the mean amount of rainfall for the month? What is the probability of less than an inch of rain for the month? What is the probability of exactly 1.00 inch of rain? What is the probability of more than 1.50 inches of rain for the month? The best way to solve this problem is begin by a step by step creating a chart. Clearly mark the range, identifying the…arrow_forwardClient 1 Weight before diet (pounds) Weight after diet (pounds) 128 120 2 131 123 3 140 141 4 178 170 5 121 118 6 136 136 7 118 121 8 136 127arrow_forward
- Client 1 Weight before diet (pounds) Weight after diet (pounds) 128 120 2 131 123 3 140 141 4 178 170 5 121 118 6 136 136 7 118 121 8 136 127 a) Determine the mean change in patient weight from before to after the diet (after – before). What is the 95% confidence interval of this mean difference?arrow_forwardIn order to find probability, you can use this formula in Microsoft Excel: The best way to understand and solve these problems is by first drawing a bell curve and marking key points such as x, the mean, and the areas of interest. Once marked on the bell curve, figure out what calculations are needed to find the area of interest. =NORM.DIST(x, Mean, Standard Dev., TRUE). When the question mentions “greater than” you may have to subtract your answer from 1. When the question mentions “between (two values)”, you need to do separate calculation for both values and then subtract their results to get the answer. 1. Compute the probability of a value between 44.0 and 55.0. (The question requires finding probability value between 44 and 55. Solve it in 3 steps. In the first step, use the above formula and x = 44, calculate probability value. In the second step repeat the first step with the only difference that x=55. In the third step, subtract the answer of the first part from the…arrow_forwardIf a uniform distribution is defined over the interval from 6 to 10, then answer the followings: What is the mean of this uniform distribution? Show that the probability of any value between 6 and 10 is equal to 1.0 Find the probability of a value more than 7. Find the probability of a value between 7 and 9. The closing price of Schnur Sporting Goods Inc. common stock is uniformly distributed between $20 and $30 per share. What is the probability that the stock price will be: More than $27? Less than or equal to $24? The April rainfall in Flagstaff, Arizona, follows a uniform distribution between 0.5 and 3.00 inches. What is the mean amount of rainfall for the month? What is the probability of less than an inch of rain for the month? What is the probability of exactly 1.00 inch of rain? What is the probability of more than 1.50 inches of rain for the month? The best way to solve this problem is begin by creating a chart. Clearly mark the range, identifying the lower and upper…arrow_forward
- Problem 1: The mean hourly pay of an American Airlines flight attendant is normally distributed with a mean of 40 per hour and a standard deviation of 3.00 per hour. What is the probability that the hourly pay of a randomly selected flight attendant is: Between the mean and $45 per hour? More than $45 per hour? Less than $32 per hour? Problem 2: The mean of a normal probability distribution is 400 pounds. The standard deviation is 10 pounds. What is the area between 415 pounds and the mean of 400 pounds? What is the area between the mean and 395 pounds? What is the probability of randomly selecting a value less than 395 pounds? Problem 3: In New York State, the mean salary for high school teachers in 2022 was 81,410 with a standard deviation of 9,500. Only Alaska’s mean salary was higher. Assume New York’s state salaries follow a normal distribution. What percent of New York State high school teachers earn between 70,000 and 75,000? What percent of New York State high school…arrow_forwardPls help asaparrow_forwardSolve the following LP problem using the Extreme Point Theorem: Subject to: Maximize Z-6+4y 2+y≤8 2x + y ≤10 2,y20 Solve it using the graphical method. Guidelines for preparation for the teacher's questions: Understand the basics of Linear Programming (LP) 1. Know how to formulate an LP model. 2. Be able to identify decision variables, objective functions, and constraints. Be comfortable with graphical solutions 3. Know how to plot feasible regions and find extreme points. 4. Understand how constraints affect the solution space. Understand the Extreme Point Theorem 5. Know why solutions always occur at extreme points. 6. Be able to explain how optimization changes with different constraints. Think about real-world implications 7. Consider how removing or modifying constraints affects the solution. 8. Be prepared to explain why LP problems are used in business, economics, and operations research.arrow_forward
- ged the variance for group 1) Different groups of male stalk-eyed flies were raised on different diets: a high nutrient corn diet vs. a low nutrient cotton wool diet. Investigators wanted to see if diet quality influenced eye-stalk length. They obtained the following data: d Diet Sample Mean Eye-stalk Length Variance in Eye-stalk d size, n (mm) Length (mm²) Corn (group 1) 21 2.05 0.0558 Cotton (group 2) 24 1.54 0.0812 =205-1.54-05T a) Construct a 95% confidence interval for the difference in mean eye-stalk length between the two diets (e.g., use group 1 - group 2).arrow_forwardAn article in Business Week discussed the large spread between the federal funds rate and the average credit card rate. The table below is a frequency distribution of the credit card rate charged by the top 100 issuers. Credit Card Rates Credit Card Rate Frequency 18% -23% 19 17% -17.9% 16 16% -16.9% 31 15% -15.9% 26 14% -14.9% Copy Data 8 Step 1 of 2: Calculate the average credit card rate charged by the top 100 issuers based on the frequency distribution. Round your answer to two decimal places.arrow_forwardPlease could you check my answersarrow_forward
- Algebra for College StudentsAlgebraISBN:9781285195780Author:Jerome E. Kaufmann, Karen L. SchwittersPublisher:Cengage LearningIntermediate AlgebraAlgebraISBN:9781285195728Author:Jerome E. Kaufmann, Karen L. SchwittersPublisher:Cengage LearningElementary AlgebraAlgebraISBN:9780998625713Author:Lynn Marecek, MaryAnne Anthony-SmithPublisher:OpenStax - Rice University
- Algebra: Structure And Method, Book 1AlgebraISBN:9780395977224Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. ColePublisher:McDougal LittellGlencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw Hill





