
The Tolien’s test for the presence of reducing sugars (say, in a urine sample) involves treating the sample with silver ions in aqueous ammonia. The result is the formation of a silver mirror within the reaction vessel if a reducing sugar is present. Using glucose, C6H12O6, to illustrate this test, the
C6H12O6 (aq) + 2 Ag+(aq) + 2OH–(aq) → C6H12O7(aq) + 2 Ag(s) + H2O(ℓ) What has been oxidized, and what has been reduced? What is the oxidizing agent, and what is the reducing agent?
Tolien's test. The reaction of silver ions with a sugar such as glucose produces metallic silver. (a) The set-up for the reaction. (b) The silvered test tube

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Chapter 3 Solutions
Bundle: Chemistry & Chemical Reactivity, Loose-Leaf Version, 9th + OWLv2, 4 terms (24 Months) Printed Access Card
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- Indicate the order of basicity of primary, secondary and tertiary amines.arrow_forward> Classify each of the following molecules as aromatic, antiaromatic, or nonaromatic. Cl Z- N O aromatic O antiaromatic O nonaromatic O aromatic O antiaromatic O nonaromatic O aromatic ○ antiaromatic nonaromaticarrow_forwardPlease help me answer this question. I don't understand how or even if this can happen in a single transformation. Please provide a detailed explanation and a drawing showing how it can happen in a single transformation. Add the necessary reagents and reaction conditions above and below the arrow in this organic reaction. If the products can't be made from the reactant with a single transformation, check the box under the drawing area instead.arrow_forward
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