ORGANIC CHEMISTRY-PRINT COMPANION (LL)
ORGANIC CHEMISTRY-PRINT COMPANION (LL)
3rd Edition
ISBN: 9781119444251
Author: Klein
Publisher: WILEY
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Chapter 3, Problem 70CP

(a)

Interpretation Introduction

Interpretation:

Among the following, the compound that is not more acidic than Water has to be identified.

Concept Introduction:

Curved arrows: Curved arrows are used to show the direction of electrons movement. It has a tail (the source of electrons, usually lone pair or bonding pair from a sigma or pi-bond) and head (the destination of electrons, usually forming new lone pair on atom or a new bond). Electrons always flow from high electron density to low electron density.

Conjugate base stability: As the acid deprotonates, the stability of conjugate base formed is analyzed on the basis of electronegativity.

(b)

Interpretation Introduction

Interpretation:

The position of equilibrium for the given reaction has to be predicted.

Concept Introduction:

Predicting position of equilibrium: By comparing the conjugate bases using their structures, the position of equilibrium can be predicted. The equilibrium favors towards the most stabilized negative charge of conjugate base.

For example: HA+B-A-+HB

In the above reaction if B- conjugate base is more stable, then equilibrium will favors formation of B-. If A- is more stable, then equilibrium will favor for formation of A- Hence, the position of equilibrium can be predicted by comparing the stability of A- and B-.

Using pKavalues to compare Acidity: In general, acid-base reaction said to reach equilibrium; the position of equilibrium is described by the term Keq. When an acid-base reaction is carried out in aqueous solution, the new term arrives by the term Ka.

pKa=-logKa

pKa Values are used as measure of acidity; a strong acid will have a low pKa and a weak acid will have a high pKa.

Using pKavalues to compare Basicity:  pKa Values are also used to compare bases; by drawing the conjugate acid of each base and compare the pKa values and identify the stronger base.

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Chapter 3 Solutions

ORGANIC CHEMISTRY-PRINT COMPANION (LL)

Ch. 3.3 - Prob. 8ATSCh. 3.3 - Prob. 9ATSCh. 3.3 - Prob. 4LTSCh. 3.3 - Prob. 10PTSCh. 3.3 - Prob. 11ATSCh. 3.3 - Prob. 12CCCh. 3.4 - Prob. 5LTSCh. 3.4 - Prob. 13PTSCh. 3.4 - Prob. 14ATSCh. 3.4 - Prob. 6LTSCh. 3.4 - Prob. 15PTSCh. 3.4 - Prob. 16ATSCh. 3.4 - Prob. 17ATSCh. 3.4 - Prob. 7LTSCh. 3.4 - Prob. 18PTSCh. 3.4 - Prob. 19PTSCh. 3.4 - Prob. 20ATSCh. 3.4 - Prob. 8LTSCh. 3.4 - Prob. 21PTSCh. 3.4 - Prob. 22ATSCh. 3.4 - Prob. 9LTSCh. 3.4 - Prob. 23PTSCh. 3.4 - Prob. 24PTSCh. 3.4 - Prob. 25ATSCh. 3.4 - Prob. 26ATSCh. 3.5 - Prob. 10LTSCh. 3.5 - Prob. 27PTSCh. 3.5 - The development of chemical sensors that can...Ch. 3.5 - Determine whether H2O would be a suitable reagent...Ch. 3.5 - Prob. 29PTSCh. 3.5 - Prob. 30ATSCh. 3.7 - Prob. 31CCCh. 3.9 - Prob. 12LTSCh. 3.9 - Prob. 32PTSCh. 3.9 - Prob. 33ATSCh. 3 - Prob. 34PPCh. 3 - Prob. 35PPCh. 3 - Prob. 36PPCh. 3 - Prob. 37PPCh. 3 - Prob. 38PPCh. 3 - Prob. 39PPCh. 3 - Prob. 40PPCh. 3 - Prob. 41PPCh. 3 - Prob. 42PPCh. 3 - Prob. 43PPCh. 3 - Prob. 44PPCh. 3 - Prob. 45PPCh. 3 - Prob. 46PPCh. 3 - Prob. 47PPCh. 3 - Prob. 48PPCh. 3 - Prob. 49IPCh. 3 - Prob. 50IPCh. 3 - Prob. 51IPCh. 3 - Prob. 52IPCh. 3 - Prob. 53IPCh. 3 - Prob. 54IPCh. 3 - Prob. 55IPCh. 3 - Prob. 56IPCh. 3 - Prob. 57IPCh. 3 - Prob. 58IPCh. 3 - Prob. 59IPCh. 3 - Prob. 60IPCh. 3 - Prob. 61IPCh. 3 - Prob. 62IPCh. 3 - Prob. 63IPCh. 3 - Prob. 64IPCh. 3 - The bengamides are a series of natural products...Ch. 3 - Prob. 66IPCh. 3 - Prob. 67IPCh. 3 - Prob. 68IPCh. 3 - Prob. 69IPCh. 3 - Prob. 70CPCh. 3 - Prob. 71CPCh. 3 - Prob. 72CPCh. 3 - Prob. 73CP
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