The equation Cr ( s ) + S 8 ( s ) → Cr 2 S 3 ( s ) is to be balanced. Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

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Answer 1

Question

Definition Definition Number that is expressed before molecules, ions, and atoms such that it balances out the number of components present on either section of the equation in a chemical reaction. Stoichiometric coefficients can be a fraction or a whole number and are useful in determining the mole ratio among the reactants and products. In any equalized chemical equation, the number of components on either side of the equation will be the same.

Chapter 3, Problem 69E

(a)

Interpretation Introduction

Interpretation: The equation $Cr(s)+S8(s)→Cr2S3(s)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

(a)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$16Cr(s)+3S8(s)→8Cr2S3(s)$

Explanation of Solution

The given equation is shown below.

$Cr(s)+S8(s)→Cr2S3(s)$

Balancing any equation involves equalizing the atoms of every element on reactant’s and product’s side.

The number of atoms of $S$ on the left-hand side is $8$ and that on right-hand side are $3$ . Therefore, in order to balance the $S$ atoms, add $3$ as the stoichiometric coefficient for $S8(s)$ and $8$ as the stoichiometric coefficient of $Cr2S3(s)$ . The equation obtained after doing this is as follows.

$Cr(s)+3S8(s)→8Cr2S3(s)$ .

Similarly, the number of atoms of $Cr$ on the right-hand side is $16$ . Therefore, in order to balance the $Cr$ atoms, add $16$ as the stoichiometric coefficient for $Cr(s)$ on left-hand side. The equation obtained after doing this is as follows.

$16Cr(s)+3S8(s)→8Cr2S3(s)$

The number of atoms of each element on each side is as follows.

$Cr=16S=24$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

(b)

Interpretation Introduction

Interpretation: The equation $NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

(b)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$2NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$

Explanation of Solution

The given equation is shown below.

$NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$

In order to balance any equation, equalize the atoms of every element on reactant’s and product’s side.

The number of atoms of $Na$ on the right-hand side is $2$ and that on left-hand side is $1$ . Therefore, in order to balance the $Na$ atoms, add $2$ as the stoichiometric coefficient for $NaHCO3(s)$ on left hand right. The equation obtained after doing this is as follows.

$2NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$

The number of atoms of each element on each side is as follows.

$Na=2H=2C=2O=6$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

(c)

Interpretation Introduction

Interpretation: The equation $KClO3(s)→HeatKCl(s)+O2(g)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

(c)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$2KClO3(s)→Heat2KCl(s)+3O2(g)$

Explanation of Solution

The given equation is shown below.

$KClO3(s)→HeatKCl(s)+O2(g)$

In order to balance any equation, equalize the atoms of every element on reactant’s and product’s side.

The number of atoms of $O$ on the right-hand side is $2$ and that on left-hand side is $3$ . Therefore, in order to balance the $O$ atoms, add $2$ as the stoichiometric coefficient for $KClO3(s)$ on left-hand right and $3$ as the stoichiometric coefficient of $O2(g)$ on right-hand side. The equation obtained after doing this is as follows.

$2KClO3(s)→HeatKCl(s)+3O2(g)$

In order to balance the number of atoms of $K$ and $Cl$ on both sides, add $2$ as the stoichiometric coefficient for $KCl(s)$ .The equation obtained after doing this is shown below.

$2KClO3(s)→Heat2KCl(s)+3O2(g)$

The number of atoms of each element on each side is as follows.

$K=2Cl=2O=6$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

(d)

Interpretation Introduction

Interpretation: The equation $Eu(s)+HF(g)→EuF3(s)+H2(g)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

(d)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$2Eu(s)+6HF(g)→2EuF3(s)+3H2(g)$

Explanation of Solution

The given equation is shown below.

$Eu(s)+HF(g)→EuF3(s)+H2(g)$

In order to balance any equation, equalize the atoms of every element on reactant’s and product’s side.

The number of atoms of $F$ on the right-hand side is $3$ and that on left-hand side is $1$ . Therefore, in order to balance the $F$ atoms, add $3$ as the stoichiometric coefficient for $HF(g)$ on left hand right .The equation obtained after doing this is as follows.

$Eu(s)+3HF(g)→EuF3(s)+H2(g)$

The number of $H$ atoms on right-hand side is $2$ and that on left-hand side is $3$ . Therefore, in order to balance the number of atoms of $H$ atoms on both sides, add $3$ as the stoichiometric coefficient for $H2(g)$ and change the stoichiometric coefficient of $HF(g)$ to $6$ . The equation obtained after doing this is as follows.

$Eu(s)+6HF(g)→EuF3(s)+3H2(g)$

Now again, the number of atoms of $F$ on the right-hand side is $3$ and that on left-hand side is $6$ . Therefore, in order to balance the $F$ atoms, add $2$ as the stoichiometric coefficient for $EuF3(s)$ on right-hand right .The equation obtained after doing this is as follows.

$Eu(s)+6HF(g)→2EuF3(s)+3H2(g)$

The number of atoms of $Eu$ on the right-hand side is $2$ and that on left-hand side is $1$ . Therefore, in order to balance the $Eu$ atoms, add $2$ as the stoichiometric coefficient for $Eu(s)$ on left-hand right .The equation obtained after doing this is shown below.

$2Eu(s)+6HF(g)→2EuF3(s)+3H2(g)$

The number of atoms of each element on each side is as follows.

$Eu=2H=6F=6$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

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Answer 2

Question

Definition Definition Number that is expressed before molecules, ions, and atoms such that it balances out the number of components present on either section of the equation in a chemical reaction. Stoichiometric coefficients can be a fraction or a whole number and are useful in determining the mole ratio among the reactants and products. In any equalized chemical equation, the number of components on either side of the equation will be the same.

Chapter 3, Problem 69E

(a)

Interpretation Introduction

Interpretation: The equation $Cr(s)+S8(s)→Cr2S3(s)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

(a)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$16Cr(s)+3S8(s)→8Cr2S3(s)$

Explanation of Solution

The given equation is shown below.

$Cr(s)+S8(s)→Cr2S3(s)$

Balancing any equation involves equalizing the atoms of every element on reactant’s and product’s side.

The number of atoms of $S$ on the left-hand side is $8$ and that on right-hand side are $3$ . Therefore, in order to balance the $S$ atoms, add $3$ as the stoichiometric coefficient for $S8(s)$ and $8$ as the stoichiometric coefficient of $Cr2S3(s)$ . The equation obtained after doing this is as follows.

$Cr(s)+3S8(s)→8Cr2S3(s)$ .

Similarly, the number of atoms of $Cr$ on the right-hand side is $16$ . Therefore, in order to balance the $Cr$ atoms, add $16$ as the stoichiometric coefficient for $Cr(s)$ on left-hand side. The equation obtained after doing this is as follows.

$16Cr(s)+3S8(s)→8Cr2S3(s)$

The number of atoms of each element on each side is as follows.

$Cr=16S=24$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

(b)

Interpretation Introduction

Interpretation: The equation $NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

(b)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$2NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$

Explanation of Solution

The given equation is shown below.

$NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$

In order to balance any equation, equalize the atoms of every element on reactant’s and product’s side.

The number of atoms of $Na$ on the right-hand side is $2$ and that on left-hand side is $1$ . Therefore, in order to balance the $Na$ atoms, add $2$ as the stoichiometric coefficient for $NaHCO3(s)$ on left hand right. The equation obtained after doing this is as follows.

$2NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$

The number of atoms of each element on each side is as follows.

$Na=2H=2C=2O=6$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

(c)

Interpretation Introduction

Interpretation: The equation $KClO3(s)→HeatKCl(s)+O2(g)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

(c)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$2KClO3(s)→Heat2KCl(s)+3O2(g)$

Explanation of Solution

The given equation is shown below.

$KClO3(s)→HeatKCl(s)+O2(g)$

In order to balance any equation, equalize the atoms of every element on reactant’s and product’s side.

The number of atoms of $O$ on the right-hand side is $2$ and that on left-hand side is $3$ . Therefore, in order to balance the $O$ atoms, add $2$ as the stoichiometric coefficient for $KClO3(s)$ on left-hand right and $3$ as the stoichiometric coefficient of $O2(g)$ on right-hand side. The equation obtained after doing this is as follows.

$2KClO3(s)→HeatKCl(s)+3O2(g)$

In order to balance the number of atoms of $K$ and $Cl$ on both sides, add $2$ as the stoichiometric coefficient for $KCl(s)$ .The equation obtained after doing this is shown below.

$2KClO3(s)→Heat2KCl(s)+3O2(g)$

The number of atoms of each element on each side is as follows.

$K=2Cl=2O=6$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

(d)

Interpretation Introduction

Interpretation: The equation $Eu(s)+HF(g)→EuF3(s)+H2(g)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

(d)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$2Eu(s)+6HF(g)→2EuF3(s)+3H2(g)$

Explanation of Solution

The given equation is shown below.

$Eu(s)+HF(g)→EuF3(s)+H2(g)$

In order to balance any equation, equalize the atoms of every element on reactant’s and product’s side.

The number of atoms of $F$ on the right-hand side is $3$ and that on left-hand side is $1$ . Therefore, in order to balance the $F$ atoms, add $3$ as the stoichiometric coefficient for $HF(g)$ on left hand right .The equation obtained after doing this is as follows.

$Eu(s)+3HF(g)→EuF3(s)+H2(g)$

The number of $H$ atoms on right-hand side is $2$ and that on left-hand side is $3$ . Therefore, in order to balance the number of atoms of $H$ atoms on both sides, add $3$ as the stoichiometric coefficient for $H2(g)$ and change the stoichiometric coefficient of $HF(g)$ to $6$ . The equation obtained after doing this is as follows.

$Eu(s)+6HF(g)→EuF3(s)+3H2(g)$

Now again, the number of atoms of $F$ on the right-hand side is $3$ and that on left-hand side is $6$ . Therefore, in order to balance the $F$ atoms, add $2$ as the stoichiometric coefficient for $EuF3(s)$ on right-hand right .The equation obtained after doing this is as follows.

$Eu(s)+6HF(g)→2EuF3(s)+3H2(g)$

The number of atoms of $Eu$ on the right-hand side is $2$ and that on left-hand side is $1$ . Therefore, in order to balance the $Eu$ atoms, add $2$ as the stoichiometric coefficient for $Eu(s)$ on left-hand right .The equation obtained after doing this is shown below.

$2Eu(s)+6HF(g)→2EuF3(s)+3H2(g)$

The number of atoms of each element on each side is as follows.

$Eu=2H=6F=6$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

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Answer 3

Question

Definition Definition Number that is expressed before molecules, ions, and atoms such that it balances out the number of components present on either section of the equation in a chemical reaction. Stoichiometric coefficients can be a fraction or a whole number and are useful in determining the mole ratio among the reactants and products. In any equalized chemical equation, the number of components on either side of the equation will be the same.

Chapter 3, Problem 69E

(a)

Interpretation Introduction

Interpretation: The equation $Cr(s)+S8(s)→Cr2S3(s)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

(a)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$16Cr(s)+3S8(s)→8Cr2S3(s)$

Explanation of Solution

The given equation is shown below.

$Cr(s)+S8(s)→Cr2S3(s)$

Balancing any equation involves equalizing the atoms of every element on reactant’s and product’s side.

The number of atoms of $S$ on the left-hand side is $8$ and that on right-hand side are $3$ . Therefore, in order to balance the $S$ atoms, add $3$ as the stoichiometric coefficient for $S8(s)$ and $8$ as the stoichiometric coefficient of $Cr2S3(s)$ . The equation obtained after doing this is as follows.

$Cr(s)+3S8(s)→8Cr2S3(s)$ .

Similarly, the number of atoms of $Cr$ on the right-hand side is $16$ . Therefore, in order to balance the $Cr$ atoms, add $16$ as the stoichiometric coefficient for $Cr(s)$ on left-hand side. The equation obtained after doing this is as follows.

$16Cr(s)+3S8(s)→8Cr2S3(s)$

The number of atoms of each element on each side is as follows.

$Cr=16S=24$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

(b)

Interpretation Introduction

Interpretation: The equation $NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

(b)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$2NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$

Explanation of Solution

The given equation is shown below.

$NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$

In order to balance any equation, equalize the atoms of every element on reactant’s and product’s side.

The number of atoms of $Na$ on the right-hand side is $2$ and that on left-hand side is $1$ . Therefore, in order to balance the $Na$ atoms, add $2$ as the stoichiometric coefficient for $NaHCO3(s)$ on left hand right. The equation obtained after doing this is as follows.

$2NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$

The number of atoms of each element on each side is as follows.

$Na=2H=2C=2O=6$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

(c)

Interpretation Introduction

Interpretation: The equation $KClO3(s)→HeatKCl(s)+O2(g)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

(c)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$2KClO3(s)→Heat2KCl(s)+3O2(g)$

Explanation of Solution

The given equation is shown below.

$KClO3(s)→HeatKCl(s)+O2(g)$

In order to balance any equation, equalize the atoms of every element on reactant’s and product’s side.

The number of atoms of $O$ on the right-hand side is $2$ and that on left-hand side is $3$ . Therefore, in order to balance the $O$ atoms, add $2$ as the stoichiometric coefficient for $KClO3(s)$ on left-hand right and $3$ as the stoichiometric coefficient of $O2(g)$ on right-hand side. The equation obtained after doing this is as follows.

$2KClO3(s)→HeatKCl(s)+3O2(g)$

In order to balance the number of atoms of $K$ and $Cl$ on both sides, add $2$ as the stoichiometric coefficient for $KCl(s)$ .The equation obtained after doing this is shown below.

$2KClO3(s)→Heat2KCl(s)+3O2(g)$

The number of atoms of each element on each side is as follows.

$K=2Cl=2O=6$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

(d)

Interpretation Introduction

Interpretation: The equation $Eu(s)+HF(g)→EuF3(s)+H2(g)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

(d)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$2Eu(s)+6HF(g)→2EuF3(s)+3H2(g)$

Explanation of Solution

The given equation is shown below.

$Eu(s)+HF(g)→EuF3(s)+H2(g)$

In order to balance any equation, equalize the atoms of every element on reactant’s and product’s side.

The number of atoms of $F$ on the right-hand side is $3$ and that on left-hand side is $1$ . Therefore, in order to balance the $F$ atoms, add $3$ as the stoichiometric coefficient for $HF(g)$ on left hand right .The equation obtained after doing this is as follows.

$Eu(s)+3HF(g)→EuF3(s)+H2(g)$

The number of $H$ atoms on right-hand side is $2$ and that on left-hand side is $3$ . Therefore, in order to balance the number of atoms of $H$ atoms on both sides, add $3$ as the stoichiometric coefficient for $H2(g)$ and change the stoichiometric coefficient of $HF(g)$ to $6$ . The equation obtained after doing this is as follows.

$Eu(s)+6HF(g)→EuF3(s)+3H2(g)$

Now again, the number of atoms of $F$ on the right-hand side is $3$ and that on left-hand side is $6$ . Therefore, in order to balance the $F$ atoms, add $2$ as the stoichiometric coefficient for $EuF3(s)$ on right-hand right .The equation obtained after doing this is as follows.

$Eu(s)+6HF(g)→2EuF3(s)+3H2(g)$

The number of atoms of $Eu$ on the right-hand side is $2$ and that on left-hand side is $1$ . Therefore, in order to balance the $Eu$ atoms, add $2$ as the stoichiometric coefficient for $Eu(s)$ on left-hand right .The equation obtained after doing this is shown below.

$2Eu(s)+6HF(g)→2EuF3(s)+3H2(g)$

The number of atoms of each element on each side is as follows.

$Eu=2H=6F=6$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

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Answer 4

Question

Definition Definition Number that is expressed before molecules, ions, and atoms such that it balances out the number of components present on either section of the equation in a chemical reaction. Stoichiometric coefficients can be a fraction or a whole number and are useful in determining the mole ratio among the reactants and products. In any equalized chemical equation, the number of components on either side of the equation will be the same.

Chapter 3, Problem 69E

(a)

Interpretation Introduction

Interpretation: The equation $Cr(s)+S8(s)→Cr2S3(s)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

(a)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$16Cr(s)+3S8(s)→8Cr2S3(s)$

Explanation of Solution

The given equation is shown below.

$Cr(s)+S8(s)→Cr2S3(s)$

Balancing any equation involves equalizing the atoms of every element on reactant’s and product’s side.

The number of atoms of $S$ on the left-hand side is $8$ and that on right-hand side are $3$ . Therefore, in order to balance the $S$ atoms, add $3$ as the stoichiometric coefficient for $S8(s)$ and $8$ as the stoichiometric coefficient of $Cr2S3(s)$ . The equation obtained after doing this is as follows.

$Cr(s)+3S8(s)→8Cr2S3(s)$ .

Similarly, the number of atoms of $Cr$ on the right-hand side is $16$ . Therefore, in order to balance the $Cr$ atoms, add $16$ as the stoichiometric coefficient for $Cr(s)$ on left-hand side. The equation obtained after doing this is as follows.

$16Cr(s)+3S8(s)→8Cr2S3(s)$

The number of atoms of each element on each side is as follows.

$Cr=16S=24$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

(b)

Interpretation Introduction

Interpretation: The equation $NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

(b)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$2NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$

Explanation of Solution

The given equation is shown below.

$NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$

In order to balance any equation, equalize the atoms of every element on reactant’s and product’s side.

The number of atoms of $Na$ on the right-hand side is $2$ and that on left-hand side is $1$ . Therefore, in order to balance the $Na$ atoms, add $2$ as the stoichiometric coefficient for $NaHCO3(s)$ on left hand right. The equation obtained after doing this is as follows.

$2NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$

The number of atoms of each element on each side is as follows.

$Na=2H=2C=2O=6$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

(c)

Interpretation Introduction

Interpretation: The equation $KClO3(s)→HeatKCl(s)+O2(g)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

(c)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$2KClO3(s)→Heat2KCl(s)+3O2(g)$

Explanation of Solution

The given equation is shown below.

$KClO3(s)→HeatKCl(s)+O2(g)$

In order to balance any equation, equalize the atoms of every element on reactant’s and product’s side.

The number of atoms of $O$ on the right-hand side is $2$ and that on left-hand side is $3$ . Therefore, in order to balance the $O$ atoms, add $2$ as the stoichiometric coefficient for $KClO3(s)$ on left-hand right and $3$ as the stoichiometric coefficient of $O2(g)$ on right-hand side. The equation obtained after doing this is as follows.

$2KClO3(s)→HeatKCl(s)+3O2(g)$

In order to balance the number of atoms of $K$ and $Cl$ on both sides, add $2$ as the stoichiometric coefficient for $KCl(s)$ .The equation obtained after doing this is shown below.

$2KClO3(s)→Heat2KCl(s)+3O2(g)$

The number of atoms of each element on each side is as follows.

$K=2Cl=2O=6$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

(d)

Interpretation Introduction

Interpretation: The equation $Eu(s)+HF(g)→EuF3(s)+H2(g)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

(d)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$2Eu(s)+6HF(g)→2EuF3(s)+3H2(g)$

Explanation of Solution

The given equation is shown below.

$Eu(s)+HF(g)→EuF3(s)+H2(g)$

In order to balance any equation, equalize the atoms of every element on reactant’s and product’s side.

The number of atoms of $F$ on the right-hand side is $3$ and that on left-hand side is $1$ . Therefore, in order to balance the $F$ atoms, add $3$ as the stoichiometric coefficient for $HF(g)$ on left hand right .The equation obtained after doing this is as follows.

$Eu(s)+3HF(g)→EuF3(s)+H2(g)$

The number of $H$ atoms on right-hand side is $2$ and that on left-hand side is $3$ . Therefore, in order to balance the number of atoms of $H$ atoms on both sides, add $3$ as the stoichiometric coefficient for $H2(g)$ and change the stoichiometric coefficient of $HF(g)$ to $6$ . The equation obtained after doing this is as follows.

$Eu(s)+6HF(g)→EuF3(s)+3H2(g)$

Now again, the number of atoms of $F$ on the right-hand side is $3$ and that on left-hand side is $6$ . Therefore, in order to balance the $F$ atoms, add $2$ as the stoichiometric coefficient for $EuF3(s)$ on right-hand right .The equation obtained after doing this is as follows.

$Eu(s)+6HF(g)→2EuF3(s)+3H2(g)$

The number of atoms of $Eu$ on the right-hand side is $2$ and that on left-hand side is $1$ . Therefore, in order to balance the $Eu$ atoms, add $2$ as the stoichiometric coefficient for $Eu(s)$ on left-hand right .The equation obtained after doing this is shown below.

$2Eu(s)+6HF(g)→2EuF3(s)+3H2(g)$

The number of atoms of each element on each side is as follows.

$Eu=2H=6F=6$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

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Answer 5

Chapter 3, Problem 69E

(a)

Interpretation Introduction

Interpretation: The equation $Cr(s)+S8(s)→Cr2S3(s)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

(a)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$16Cr(s)+3S8(s)→8Cr2S3(s)$

Explanation of Solution

The given equation is shown below.

$Cr(s)+S8(s)→Cr2S3(s)$

Balancing any equation involves equalizing the atoms of every element on reactant’s and product’s side.

The number of atoms of $S$ on the left-hand side is $8$ and that on right-hand side are $3$ . Therefore, in order to balance the $S$ atoms, add $3$ as the stoichiometric coefficient for $S8(s)$ and $8$ as the stoichiometric coefficient of $Cr2S3(s)$ . The equation obtained after doing this is as follows.

$Cr(s)+3S8(s)→8Cr2S3(s)$ .

Similarly, the number of atoms of $Cr$ on the right-hand side is $16$ . Therefore, in order to balance the $Cr$ atoms, add $16$ as the stoichiometric coefficient for $Cr(s)$ on left-hand side. The equation obtained after doing this is as follows.

$16Cr(s)+3S8(s)→8Cr2S3(s)$

The number of atoms of each element on each side is as follows.

$Cr=16S=24$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

(b)

Interpretation Introduction

Interpretation: The equation $NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

(b)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$2NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$

Explanation of Solution

The given equation is shown below.

$NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$

In order to balance any equation, equalize the atoms of every element on reactant’s and product’s side.

The number of atoms of $Na$ on the right-hand side is $2$ and that on left-hand side is $1$ . Therefore, in order to balance the $Na$ atoms, add $2$ as the stoichiometric coefficient for $NaHCO3(s)$ on left hand right. The equation obtained after doing this is as follows.

$2NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$

The number of atoms of each element on each side is as follows.

$Na=2H=2C=2O=6$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

(c)

Interpretation Introduction

Interpretation: The equation $KClO3(s)→HeatKCl(s)+O2(g)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

(c)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$2KClO3(s)→Heat2KCl(s)+3O2(g)$

Explanation of Solution

The given equation is shown below.

$KClO3(s)→HeatKCl(s)+O2(g)$

In order to balance any equation, equalize the atoms of every element on reactant’s and product’s side.

The number of atoms of $O$ on the right-hand side is $2$ and that on left-hand side is $3$ . Therefore, in order to balance the $O$ atoms, add $2$ as the stoichiometric coefficient for $KClO3(s)$ on left-hand right and $3$ as the stoichiometric coefficient of $O2(g)$ on right-hand side. The equation obtained after doing this is as follows.

$2KClO3(s)→HeatKCl(s)+3O2(g)$

In order to balance the number of atoms of $K$ and $Cl$ on both sides, add $2$ as the stoichiometric coefficient for $KCl(s)$ .The equation obtained after doing this is shown below.

$2KClO3(s)→Heat2KCl(s)+3O2(g)$

The number of atoms of each element on each side is as follows.

$K=2Cl=2O=6$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

(d)

Interpretation Introduction

Interpretation: The equation $Eu(s)+HF(g)→EuF3(s)+H2(g)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

(d)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$2Eu(s)+6HF(g)→2EuF3(s)+3H2(g)$

Explanation of Solution

The given equation is shown below.

$Eu(s)+HF(g)→EuF3(s)+H2(g)$

In order to balance any equation, equalize the atoms of every element on reactant’s and product’s side.

The number of atoms of $F$ on the right-hand side is $3$ and that on left-hand side is $1$ . Therefore, in order to balance the $F$ atoms, add $3$ as the stoichiometric coefficient for $HF(g)$ on left hand right .The equation obtained after doing this is as follows.

$Eu(s)+3HF(g)→EuF3(s)+H2(g)$

The number of $H$ atoms on right-hand side is $2$ and that on left-hand side is $3$ . Therefore, in order to balance the number of atoms of $H$ atoms on both sides, add $3$ as the stoichiometric coefficient for $H2(g)$ and change the stoichiometric coefficient of $HF(g)$ to $6$ . The equation obtained after doing this is as follows.

$Eu(s)+6HF(g)→EuF3(s)+3H2(g)$

Now again, the number of atoms of $F$ on the right-hand side is $3$ and that on left-hand side is $6$ . Therefore, in order to balance the $F$ atoms, add $2$ as the stoichiometric coefficient for $EuF3(s)$ on right-hand right .The equation obtained after doing this is as follows.

$Eu(s)+6HF(g)→2EuF3(s)+3H2(g)$

The number of atoms of $Eu$ on the right-hand side is $2$ and that on left-hand side is $1$ . Therefore, in order to balance the $Eu$ atoms, add $2$ as the stoichiometric coefficient for $Eu(s)$ on left-hand right .The equation obtained after doing this is shown below.

$2Eu(s)+6HF(g)→2EuF3(s)+3H2(g)$

The number of atoms of each element on each side is as follows.

$Eu=2H=6F=6$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

Answer 6

Chapter 3, Problem 69E

(a)

Interpretation Introduction

Interpretation: The equation $Cr(s)+S8(s)→Cr2S3(s)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

(a)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$16Cr(s)+3S8(s)→8Cr2S3(s)$

Explanation of Solution

The given equation is shown below.

$Cr(s)+S8(s)→Cr2S3(s)$

Balancing any equation involves equalizing the atoms of every element on reactant’s and product’s side.

The number of atoms of $S$ on the left-hand side is $8$ and that on right-hand side are $3$ . Therefore, in order to balance the $S$ atoms, add $3$ as the stoichiometric coefficient for $S8(s)$ and $8$ as the stoichiometric coefficient of $Cr2S3(s)$ . The equation obtained after doing this is as follows.

$Cr(s)+3S8(s)→8Cr2S3(s)$ .

Similarly, the number of atoms of $Cr$ on the right-hand side is $16$ . Therefore, in order to balance the $Cr$ atoms, add $16$ as the stoichiometric coefficient for $Cr(s)$ on left-hand side. The equation obtained after doing this is as follows.

$16Cr(s)+3S8(s)→8Cr2S3(s)$

The number of atoms of each element on each side is as follows.

$Cr=16S=24$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

Answer 7

Chapter 3, Problem 69E

(a)

Interpretation Introduction

Interpretation: The equation $Cr(s)+S8(s)→Cr2S3(s)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

Answer 8

(a)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$16Cr(s)+3S8(s)→8Cr2S3(s)$

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

The given equation is shown below.

$Cr(s)+S8(s)→Cr2S3(s)$

Balancing any equation involves equalizing the atoms of every element on reactant’s and product’s side.

The number of atoms of $S$ on the left-hand side is $8$ and that on right-hand side are $3$ . Therefore, in order to balance the $S$ atoms, add $3$ as the stoichiometric coefficient for $S8(s)$ and $8$ as the stoichiometric coefficient of $Cr2S3(s)$ . The equation obtained after doing this is as follows.

$Cr(s)+3S8(s)→8Cr2S3(s)$ .

Similarly, the number of atoms of $Cr$ on the right-hand side is $16$ . Therefore, in order to balance the $Cr$ atoms, add $16$ as the stoichiometric coefficient for $Cr(s)$ on left-hand side. The equation obtained after doing this is as follows.

$16Cr(s)+3S8(s)→8Cr2S3(s)$

The number of atoms of each element on each side is as follows.

$Cr=16S=24$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

Answer 13

(b)

Interpretation Introduction

Interpretation: The equation $NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

(b)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$2NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$

Explanation of Solution

The given equation is shown below.

$NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$

In order to balance any equation, equalize the atoms of every element on reactant’s and product’s side.

The number of atoms of $Na$ on the right-hand side is $2$ and that on left-hand side is $1$ . Therefore, in order to balance the $Na$ atoms, add $2$ as the stoichiometric coefficient for $NaHCO3(s)$ on left hand right. The equation obtained after doing this is as follows.

$2NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$

The number of atoms of each element on each side is as follows.

$Na=2H=2C=2O=6$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

Answer 14

(b)

Interpretation Introduction

Interpretation: The equation $NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

Answer 15

(b)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$2NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

The given equation is shown below.

$NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$

In order to balance any equation, equalize the atoms of every element on reactant’s and product’s side.

The number of atoms of $Na$ on the right-hand side is $2$ and that on left-hand side is $1$ . Therefore, in order to balance the $Na$ atoms, add $2$ as the stoichiometric coefficient for $NaHCO3(s)$ on left hand right. The equation obtained after doing this is as follows.

$2NaHCO3(s)→HeatNa2CO3(s)+CO2(g)+H2O(g)$

The number of atoms of each element on each side is as follows.

$Na=2H=2C=2O=6$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

Answer 20

(c)

Interpretation Introduction

Interpretation: The equation $KClO3(s)→HeatKCl(s)+O2(g)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

(c)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$2KClO3(s)→Heat2KCl(s)+3O2(g)$

Explanation of Solution

The given equation is shown below.

$KClO3(s)→HeatKCl(s)+O2(g)$

In order to balance any equation, equalize the atoms of every element on reactant’s and product’s side.

The number of atoms of $O$ on the right-hand side is $2$ and that on left-hand side is $3$ . Therefore, in order to balance the $O$ atoms, add $2$ as the stoichiometric coefficient for $KClO3(s)$ on left-hand right and $3$ as the stoichiometric coefficient of $O2(g)$ on right-hand side. The equation obtained after doing this is as follows.

$2KClO3(s)→HeatKCl(s)+3O2(g)$

In order to balance the number of atoms of $K$ and $Cl$ on both sides, add $2$ as the stoichiometric coefficient for $KCl(s)$ .The equation obtained after doing this is shown below.

$2KClO3(s)→Heat2KCl(s)+3O2(g)$

The number of atoms of each element on each side is as follows.

$K=2Cl=2O=6$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

Answer 21

(c)

Interpretation Introduction

Interpretation: The equation $KClO3(s)→HeatKCl(s)+O2(g)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

Answer 22

(c)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$2KClO3(s)→Heat2KCl(s)+3O2(g)$

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

The given equation is shown below.

$KClO3(s)→HeatKCl(s)+O2(g)$

In order to balance any equation, equalize the atoms of every element on reactant’s and product’s side.

The number of atoms of $O$ on the right-hand side is $2$ and that on left-hand side is $3$ . Therefore, in order to balance the $O$ atoms, add $2$ as the stoichiometric coefficient for $KClO3(s)$ on left-hand right and $3$ as the stoichiometric coefficient of $O2(g)$ on right-hand side. The equation obtained after doing this is as follows.

$2KClO3(s)→HeatKCl(s)+3O2(g)$

In order to balance the number of atoms of $K$ and $Cl$ on both sides, add $2$ as the stoichiometric coefficient for $KCl(s)$ .The equation obtained after doing this is shown below.

$2KClO3(s)→Heat2KCl(s)+3O2(g)$

The number of atoms of each element on each side is as follows.

$K=2Cl=2O=6$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

Answer 27

(d)

Interpretation Introduction

Interpretation: The equation $Eu(s)+HF(g)→EuF3(s)+H2(g)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

(d)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$2Eu(s)+6HF(g)→2EuF3(s)+3H2(g)$

Explanation of Solution

The given equation is shown below.

$Eu(s)+HF(g)→EuF3(s)+H2(g)$

In order to balance any equation, equalize the atoms of every element on reactant’s and product’s side.

The number of atoms of $F$ on the right-hand side is $3$ and that on left-hand side is $1$ . Therefore, in order to balance the $F$ atoms, add $3$ as the stoichiometric coefficient for $HF(g)$ on left hand right .The equation obtained after doing this is as follows.

$Eu(s)+3HF(g)→EuF3(s)+H2(g)$

The number of $H$ atoms on right-hand side is $2$ and that on left-hand side is $3$ . Therefore, in order to balance the number of atoms of $H$ atoms on both sides, add $3$ as the stoichiometric coefficient for $H2(g)$ and change the stoichiometric coefficient of $HF(g)$ to $6$ . The equation obtained after doing this is as follows.

$Eu(s)+6HF(g)→EuF3(s)+3H2(g)$

Now again, the number of atoms of $F$ on the right-hand side is $3$ and that on left-hand side is $6$ . Therefore, in order to balance the $F$ atoms, add $2$ as the stoichiometric coefficient for $EuF3(s)$ on right-hand right .The equation obtained after doing this is as follows.

$Eu(s)+6HF(g)→2EuF3(s)+3H2(g)$

The number of atoms of $Eu$ on the right-hand side is $2$ and that on left-hand side is $1$ . Therefore, in order to balance the $Eu$ atoms, add $2$ as the stoichiometric coefficient for $Eu(s)$ on left-hand right .The equation obtained after doing this is shown below.

$2Eu(s)+6HF(g)→2EuF3(s)+3H2(g)$

The number of atoms of each element on each side is as follows.

$Eu=2H=6F=6$

Since, the number of atoms of each element is equal on both sides; therefore the above equation is balanced.

Answer 28

(d)

Interpretation Introduction

Interpretation: The equation $Eu(s)+HF(g)→EuF3(s)+H2(g)$ is to be balanced.

Concept introduction: Balancing any equation is important in order to know how many atoms of any element are participating in given reaction. Moreover, balancing of any equation is done to follow law of mass conservation and also for various stoichiometric calculations. Introducing stoichiometric coefficients for participants assist in balancing the reaction.

Answer 29

(d)

Expert Solution

Answer to Problem 69E

The balanced equation is shown below.

$2Eu(s)+6HF(g)→2EuF3(s)+3H2(g)$

Answer 30

(d)

Expert Solution

Answer 31

(d)

Expert Solution

Answer 32

Expert Solution

Answer 33

Explanation of Solution

The given equation is shown below.

$Eu(s)+HF(g)→EuF3(s)+H2(g)$

In order to balance any equation, equalize the atoms of every element on reactant’s and product’s side.

The number of atoms of $F$ on the right-hand side is $3$ and that on left-hand side is $1$ . Therefore, in order to balance the $F$ atoms, add $3$ as the stoichiometric coefficient for $HF(g)$ on left hand right .The equation obtained after doing this is as follows.

$Eu(s)+3HF(g)→EuF3(s)+H2(g)$

The number of $H$ atoms on right-hand side is $2$ and that on left-hand side is $3$ . Therefore, in order to balance the number of atoms of $H$ atoms on both sides, add $3$ as the stoichiometric coefficient for $H2(g)$ and change the stoichiometric coefficient of $HF(g)$ to $6$ . The equation obtained after doing this is as follows.

$Eu(s)+6HF(g)→EuF3(s)+3H2(g)$

Now again, the number of atoms of $F$ on the right-hand side is $3$ and that on left-hand side is $6$ . Therefore, in order to balance the $F$ atoms, add $2$ as the stoichiometric coefficient for $EuF3(s)$ on right-hand right .The equation obtained after doing this is as follows.

$Eu(s)+6HF(g)→2EuF3(s)+3H2(g)$

The number of atoms of $Eu$ on the right-hand side is $2$ and that on left-hand side is $1$ . Therefore, in order to balance the $Eu$ atoms, add $2$ as the stoichiometric coefficient for $Eu(s)$ on left-hand right .The equation obtained after doing this is shown below.