Advanced Placement Calculus 2016 Graphical Numerical Algebraic Fifth Edition Student Edition
5th Edition
ISBN: 9780133311617
Author: Prentice Hall
Publisher: Prentice Hall
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Students have asked these similar questions
Ohm's law states that the voltage drop Vacross an ideal resistor is linearly proportional
to the current i flowing through the resistor as V= iR. Where R is the resistance. However,
real resistors may not always obey Ohm's law. Suppose that you perform some very
precise experiments to measure the voltage drop and the corresponding current for a
resistor. The following results suggest a curvilinear relationship rather than the straight
line represented by Ohm's law.
i
-1
- 0.5
- 0.25
0.25
0.5
1
V
-637
-96.5
-20.25
20.5
96.5
637
Instead of the typical linear regression method for analyzing such experimental data, fit a
curve to the data to quantify the relationship. Compute V for i = 0.1 using Polynomial
Interpolation.
Ohm's law states that the voltage drop Vacross an ideal resistor is linearly proportional
to the current i flowing through the resistor as V= iR. Where R is the resistance. However,
real resistors may not always obey Ohm's law. Suppose that you perform some very
precise experiments to measure the voltage drop and the corresponding current for a
resistor. The following results suggest a curvilinear relationship rather than the straight
line represented by Ohm's law.
i
-1
- 0.5
- 0.25
0.25
0.5
1
V
-637
-96.5
-20.25
20.5
96.5
637
Instead of the typical linear regression method for analyzing such experimental data, fit a
curve to the data to quantify the relationship. Compute V for i = 0.1 using Newton's
Divided Difference Method.
Part 2. Math column A to column B by finding the slope of tangent line at any given point and write the letter of
your answer on the space provided.
Column A
Column B
A. y = 2x - 7
1. y 4x2- 4x +1 at point (1,1)
B. y = x-9
2x-5
_2. y =
at point (1,5)
7-2x
C. y = *
3. у %3D х +3
at point (4,1)
D. y = 2x - 10
4. y = x² - 4
at point (-2,-4)
E. y = 2
5. у %3D Зх — 5
at point (-2,3)
F. y = 3x - 5
6. y = 4x2 + 2
at point (0,0)
G. y = -4x-8
7. y = 2x- 10
at point (4,2)
H. y = x+ 3
8. y =
x+4
at point (-2,-)
X-4
I. y = 5x -9
%3D
9.y x-9
at point (3,1)
J. y = 4x- 3
10. y = x2 - 6
at point (1,2)
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