PROGRAMMABLE LOGIC CONTROLLERS (LOOSE PA
PROGRAMMABLE LOGIC CONTROLLERS (LOOSE PA
5th Edition
ISBN: 9781264206216
Author: Petruzella
Publisher: MCG
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Chapter 3, Problem 5RQ

Conversion of hexadecimal numbers to decimal numbers:

a.

Explanation of Solution

5A:

  • • Given, hexadecimal number is 5A.
  • • First, multiply the given hexadecimal number 5A with multiples of 16, with respect to their positions and then, add all the values to get the final answer.
  • • The following calculation describes the decimal notation of the hexadecimal number 5A.

5A=161*5+160*A =161*5+160*10 <

b.

Explanation of Solution

C7:

  • • Given, hexadecimal number is C7.
  • • First, multiply the given hexadecimal number C7 with multiples of 16, with respect to their positions and then, add all the values to get the final answer.
  • • The following calculation describes the decimal notation of the hexadecimal number C7.

C7=161*C+160*7 =161*12+160*7 =<

c.

Explanation of Solution

9B5:

  • • Given, hexadecimal number is 9B5.
  • • First, multiply the given hexadecimal number 9B5 with multiples of 16, with respect to their positions and then, add all the values to get the final answer.
  • • The following calculation describes the decimal notation of the hexadecimal number 9B5.

9B5=162*9+161*B+160*5 =162*9+161*11+160*5

Explanation of Solution

d.

1A6:

  • • Given, hexadecimal number is 1A6.
  • • First, multiply the given hexadecimal number 1A6 with multiples of 16, with respect to their positions and then, add all the values to get the final answer.
  • • The following calculation describes the decimal notation of the hexadecimal number 1A6.

1A6=162*1+161*A+160*6 =162*1+161*10+160*6 &

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⚫ your circuit diagrams for your basic bricks, such as AND, OR, XOR gates and 1 bit multiplexers, ⚫ your circuit diagrams for your extended full adder, designed in Section 1 and ⚫ your circuit diagrams for your 8-bit arithmetical-logical unit, designed in Section 2. 1 An Extended Full Adder In this Section, we are going to design an extended full adder circuit (EFA). That EFA takes 6 one bit inputs: aj, bj, Cin, Tin, t₁ and to. Depending on the four possible combinations of values on t₁ and to, the EFA produces 3 one bit outputs: sj, Cout and rout. The EFA can be specified in principle by a truth table with 26 = 64 entries and 3 outputs. However, as the EFA ignores certain inputs in certain cases, it is easier to work with the following overview specification, depending only on t₁ and to in the first place: t₁ to Description 00 Output Relationship Ignored Inputs Addition Mode 2 Coutsjaj + bj + Cin, Tout= 0 Tin 0 1 Shift Left Mode Sj = Cin, Cout=bj, rout = 0 rin, aj 10 1 1 Shift Right…
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