Chapter 3, Problem 51RE

A small church choir is made up of men and women who wear choir robes in the sizes shown in matrix $A$.

$\begin{array}{l}\begin{array}{cccc}& \text{Men}& \text{Women}& \end{array}\\ \text{A=}\left[\begin{array}{rrr}\hfill 1& \hfill & \hfill 14\\ \hfill 12& \hfill & \hfill 10\\ \hfill 8& \hfill & \hfill 3\end{array}\right]\begin{array}{l}\text{Small}\hfill \\ \text{Medium}\hfill \\ \text{Large}\hfill \end{array}\end{array}$

$\begin{array}{l}\begin{array}{llllll}\hfill & \text{S}\hfill & \text{M}\hfill & \text{L}\hfill & \hfill & \hfill \end{array}\\ B\text{=}\left[\begin{array}{rrr}\hfill \text{25}& \hfill \text{40}& \hfill \text{45}\\ \hfill \text{10}& \hfill \text{10}& \hfill \text{10}\end{array}\right]\begin{array}{l}\text{Robes}\hfill \\ \text{Hoods}\hfill \end{array}\end{array}$

Matrix $B$

contains the prices (in dollars) of new robes and hoods according to size. Use these matrices in Problems 50 and 51.

Cost To find a matrix that gives the cost of new robes and cost of new hoods, find

$BA\left[\begin{array}{c}1\\ 1\end{array}\right]$