Concept explainers
Interpretation:
The presence of two separate layers, when aqueous sodium bicarbonate is added to an organic reaction mixture, is to be explained on the basis of solubility and polarity. The chemical species present in both aqueous and organic layers after reaction with sodium bicarbonate is to be listed. The reason to repeat sodium bicarbonate extraction thrice is to be mentioned.
Concept introduction:
According to acid–base chemistry, in a liquid/liquid extraction containing two immiscible liquids, the more polar compound dissolves in the aqueous layer, whereas the organic compound dissolves in the non-polar phase. The distribution coefficient gives the ratio of the concentration of the solute in a mixture of two immiscible solvents at equilibrium.
An organic compound will dissolve better in the organic layer than in most aqueous solutions, unless it has been converted to an ionic species, which makes it more water-soluble.
Sodium bicarbonate is used for the extraction in order to neutralize or remove acidic compounds.
A separating funnel is used to separate the mixture components between two liquids that are immiscible.
One phase is the aqueous and the other one is organic solvent.
This separation depends on the densities of the liquids.
The separating funnel runs on the concept of “like dissolve like” with different solutes being preferentially soluble in certain solvent.
When separating funnel is shaken, the two solvents mix and share a large surface area, which allows each solute to migrate to the solvent in which it is more soluble.
Le Chateliers principle is used to explain the change in pressure, temperature or concentration of the equilibrium shifts into the direction in which effect change from the system.

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Chapter 3 Solutions
ORGANIC CHEMISTRY (LL) W/WILEYPLUS NEXT
- H-Br Energy 1) Draw the step-by-step mechanism by which 3-methylbut-1-ene is converted into 2-bromo-2-methylbutane. 2) Sketch a reaction coordinate diagram that shows how the internal energy (Y- axis) of the reacting species change from reactants to intermediate(s) to product. Brarrow_forward2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). C5H10 H-CI CH2Cl2 CIarrow_forwardDraw the products of the stronger acid protonating the other reactant. དའི་སྐད”“ H3C OH H3C CH CH3 KEq Product acid Product basearrow_forward
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- 2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). C5H10 Br H-Br CH2Cl2 + enant.arrow_forwardDraw the products of the stronger acid protonating the other reactant. KEq H₂C-O-H H3C OH Product acid Product basearrow_forwardDraw the products of the stronger acid protonating the other reactant. OH KEq CH H3C H3C `CH3 Product acid Product basearrow_forward
- 2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). Ph H-I CH2Cl2arrow_forward3 attempts left Check my work Draw the products formed in the following oxidative cleavage. [1] 03 [2] H₂O draw structure ... lower mass product draw structure ... higher mass productarrow_forward2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). H-Br CH2Cl2arrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
