Explanation Given information: The Magnitude of vector A → is 1.0 m and points 35 ° clockwise from x -axis. The Magnitude of vector B → is 1.8 m. Calculation: The vector A → points 35 ° clockwise from x -axis. Therefore, θ A = − 35 ° . Express the vector A → as, A → = A x i ^ + A y j ^ (1) Here, A x is the x -component displacement, A y is the y -component displacement, i ^ is the unit vector in x -direction, and j ^ is the unit vector in y -direction. The x -component displacement of A is A x = A cos θ A . Here, θ A is the angle of A . Express the vector B → as follows: B → = B x i ^ + B y j ^ (2) The x -component displacement of B is B x = B cos θ B . Here, θ B is the angle of B . Add Equation (1) and Equation (2). A → + B → = A x i ^ + A y j ^ + B x i ^ + B y j ^ = ( A x + B x ) i ^ + ( A y + B y ) j ^ Given A → + B → is in the y -direction

Essential University Physics (3rd Edition)

3rd Edition

ISBN: 9780134202709

Author: Richard Wolfson

Publisher: PEARSON

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Chapter 3, Problem 46P

To determine

The direction of B→ .

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Chapter 3, Problem 45P

Chapter 3, Problem 47P

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